Answer:
V0=27.4 m/s; t=0.8 s
Explanation:
Final position y=37.0 m, time = 2.3 s; Initial position is set to be zero. We calculate the initial speed with the kinematics equation:
We solve for initial speed
Now, using the same expression we estimated time to first reach 18.5 m :
Second order equation with solutions
t1=0.8 s and t2=4.8 s
The first time corresponds to the first reach.
Answer:
1.12μC
Explanation:
From the expression use to determine the capacitance of a capacitor, which is given below
from the above since the distance,"d" is given is 1.1mm(0.0011m)
Area= 0.3m*0.08=0.024m
V=5.8KV
if we compare both equations above, we can do away with the capacitance
if we substitute the value of the voltage, area, distance and the constant we arrive at
Hence the magnitude of the charge is 1.12μC
A centre - seeking force related to acceleration is centripetal force.
<em><u>Answer:</u></em>
zero acceleration
<em><u>Explanation:</u></em>
<u>Acceleration</u> is defined as the rate change of velocity with respect to time
<u>This means that:</u>
Now, since the velocity is given as a constant, this means that the value of the velocity does not change which means that the change of velocity is zero.
<u>Substitute in the formula:</u>
<u>Therefore,</u> for constant velocity, the acceleration is zero.
Hope this helps :)