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Alexxx [7]
3 years ago
5

What detects the original stimulus ?

Physics
1 answer:
FinnZ [79.3K]3 years ago
8 0
Wherever the change in the body happened will detect the stimuli and send the signals to the brain and Spinal does
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Applications of pressure
Sunny_sXe [5.5K]
  • hydraulic press
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3 0
2 years ago
What is the modern<br> Jatomic theory?
torisob [31]

<u>Answer:</u>

The modern atomic theory has given by "John Dalton and framed postulates".

<u>Explanation:</u>

The fundamental role of atoms in chemistry is established by the modern theory of atoms mentioned in 1808 for the first time by an English scientist named John Dalton. This consists of three sections such as all matter is composed of atoms, atoms of the same element are the same while atoms of different elements are different, atoms combine to form compounds in full-number ratios.

The unique characteristic of the "number of protons" is that all atoms of the same compound share. While the atoms of the same element i.e having a similar number of protons can have different numbers of neutrons and such elements are called isotopes.

5 0
3 years ago
• what is the typical distance between two adjacent pins on a 14-pin dual-in-line ic package?
muminat

A 14 pin dual-in-line IC package[14 DIL] is an integrated socket which is most popular form of IC package and has a wide range of application in digital electronics.

The 14-pin DIL has two pairs per side and each pair contains seven connecting pins.

The pairs of pins are arranged linearly one after another.The typical dimensions of width is 6.5 mm and the typical dimension of length is 18 mm.

we are asked to calculate the typical distance between two adjacent pins.

The typical distance between two adjacent pins is calculated as-

                                                                 Typical\ distance =\frac{dimensional\ length}{number\ of\ pins\ in\ each\ row}

                                    =\frac{18 mm}{7}

                                    = 2.5714 mm    [ans]                  

7 0
3 years ago
I need help with this question I’m not sure where to even begin
Strike441 [17]

We will have the following:

a. We determine the tension force of T2 as follows:

We know that the system must be at equilibrium on the horizontal axis:

\sum F_x=T_1cos(42.5)+T_2cos(36.5)=0

So:

\begin{gathered} T_2cos(36.5)=-(1235N)cos(42.5)\Rightarrow T_2=-\frac{(1235N)cos(42.5)}{cos(36.5)} \\  \\ \Rightarrow T_2=1132.711003...N\Rightarrow T_2\approx1132.7N \end{gathered}

So, the value of T2 is approximately 1132.7 N.

b. We will determine the torques created by T1 and T2 as follows:

T1:

\tau_{T1}=(10m)(1235N)sin(42.5)\Rightarrow\tau_{T1}\approx8343.5N\ast m

T2:

\tau_{T2}=(10m)(1132.7N)sin(36.5)\Rightarrow\tau_{T2}\approx6737.6N\ast m

So the torques of T1 and T2 on the base are approximately 8343.5 N*m and 6737.6 N*m respectively.

c. The torques around that axis generated by the normal force and the weight are both 0 N*, since they are parallel to the axis.

d. We will determine the angular acceleration as follows:

\begin{gathered} \alpha=\frac{\tau_{T1}}{I}\Rightarrow\alpha=\frac{\tau_{T1}}{(1/3mL^2)} \\  \\ \Rightarrow\alpha=\frac{(8343.5N\ast m)}{(1/3(200kg)(10m)^2)}\Rightarrow\alpha=1.251525rad/s^2 \\  \\ \Rightarrow\alpha\approx1.25rad/s^2 \end{gathered}

So, the angular acceleration is approximately 1.25 radians/ s^2.

6 0
1 year ago
Blocks A (mass 2.00 kg) and B (mass 6.00 kg) move on a frictionless, horizontal surface. Initially, block B is at rest and block
anygoal [31]

Answer:

A) U_max = 3 J ; V_a = 0.5 m/s and V_b = 0.5 m/s

B) V_a = 0.25 m/s

V_b = 2.25 m/s

Explanation:

The collision is an elastic collision and thus the energy and momentum are conserved.

We are given;

Mass of Block A; m_a = 2 kg

Mass of Block B; m_b = 6 kg

Initial velocity of Block A; v_ai = 2 m/s

Initial velocity of Block B; v_bi = 0 m/s

A) Thus, total initial kinetic energy is;

KE_initial = ½m_a•v_ai² + ½m_b•v_bi²

Thus;

KE_initial = (½ × 2 × 2²) + (½ × 6 × 0)

KE_initial = 4 J

Now, since they stick together after collision, we can calculate the velocity with which they move together from;

m_a•v_ai + m_b•v_bi = (m_a + m_b)v_2

Where v_2 is the velocity with which they move after sticking together.

v_2 = (m_a•v_ai + m_b•v_bi)/(m_a + m_b)

Plugging in the relevant values, we have;

v_2 = ((2 × 2) + (6 × 0))/(2 + 6)

v_2 = 4/8

v_2 = 0.5 m/s

Final Kinetic energy is;

KE_2 = ½(m_a + m_b) × (v_2)²

KE_2 = ½(2 + 6) × 0.5²

KE_2 = 1 J

Thus, maximum energy stored in the spring bumpers is;

U_max = KE_initial - K_final

U_max = 4 - 1

U_max = 3 J

Since objects A & B, stick together after collision, they will both move with velocity v_2

Thus, at that point, V_a = 0.5 m/s and V_b = 0.5 m/s

B) For elastic collision that's head on, we know that;

Relative velocity of approach = Relative velocity of

separation

Thus;

2 - 0 = V_b - V_a

V_b - V_a = 2

V_b = V_a + 2

From conservation of momentum;

m_a•V_a + m_b•V_b = (m_a + m_b)v_2

We saw earlier that V_b = V_a + 2

Thus;

m_a•V_a + m_b(V_a + 2) = (m_a + m_b)v_2

Plugging in the relevant values;

2(V_a) + 6(V_a + 2) = (2 + 6) × 0.5

2V_a + 6V_a + 2 = 8 × 0.5

8V_a + 2 = 4

8V_a = 4 - 2

8V_a = 2

V_a = 2/8

V_a = 0.25 m/s

From earlier, we saw that;

V_b = V_a + 2

Thus;

V_b = 0.25 + 2

V_b = 2.25 m/s

7 0
3 years ago
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