a function that model the number of people that receives email in week t is
.
<u>Step-by-step explanation:</u>
Here we have , Tobias sent a chain letter to his friends . The number of people who receives the email increases by a factor of 4 in every 9.1 weeks , and can be modeled by a function P, which depends on the amount of time t weeks . Tobias initially sent letter to 37 friends . We need to write a function that model the number of people that receives email in week t . Let's find out:
Basically it's an exponential function as
, In question initial value is 37 & and for every 9.1 weeks there is increase in people by a factor of 4 i.e.
⇒ 
But , wait ! People increase in every 9.1 weeks not every week so modified equation will be :
⇒
Therefore , a function that model the number of people that receives email in week t is
.
Answer: After 7 years the number of birds of species A and B are same. and the number of birds during that year will be 140.
Step-by-step explanation:
Given: Sharon is conducting research on two species of birds at a bird sanctuary.
The number of birds of species A is represented by the equation below,where S represents the number of birds, x years after beginning her research.

The number of birds of species B is represented by the equation below,where S represents the number of birds, x years after beginning her research.

To plot the above function, first find points by which they are passing.
For species A, At x=0 , 
At x=2 , 
Similarly find more points and plot curve on graph.
For species A, At x=0 , 
At x=2 , 
Plot a line with the help of these two points.
Now, from the graph the intersection of curve (for A) and line (for B) is at (7,140) which tells that After 7 years the number of birds of species A and B are same. and the number of birds during that year will be 140.
Answer:
look at the picture i have sent
OK so there is 72% of the company left to share. Divide that by six you get 12.
Each shareholder has 12% of the company.
Answer:
0.80A + 0.92B = 63 .....1
A + B = 75 ......2
Step-by-step explanation:
Let A and B represent the total possible score in part A and B respectively;
Analysing each sentence of the question;
Sam scored 80% on Part A of a math test and 92% on part B of the math test. His total mark on the test was 63
80% of A + 92% of B = 63
0.80A + 0.92B = 63 ......1
The total possible marks for the test was 75;
A + B = 75 .....2
So, equation 1 and 2 provides a set of simultaneous equations that can be used to represent and solve the situation.
Solving the simultaneous equations, we will arrive at;
Part A = 50
Part B = 25