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elena55 [62]
3 years ago
6

KClO₃ → Kelt Oz

Chemistry
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

5.2 moles of  KClO₃  are needed

Explanation:

Given data:

Number of moles of potassium chlorate needed = ?

Number of moles of O₂ formed = 7.8 mol

Solution:

Chemical equation:

2KClO₃      →     2KCl + 3O₂

now we will compare the moles of KClO₃ and  O₂.

                   O₂        :         KClO₃    

                    3          :           2

                   7.8        :          2/3×7.8 = 5.2

5.2 moles of  KClO₃  are needed.

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How much concentrated 18M sulfuric acid is needed to prepare 250mL of a 6.0M solution?
slavikrds [6]
C₁ * V₁ = C₂ * V₂ 

18 * V₁ = 6.0 * 250

18 V₁ = 1500

V₁ = 1500 / 18

V₁ = 83.33 mL

hope this helps!


5 0
3 years ago
The density of concentrated ammonia, which is 28.0% w/w nh3, is 0.899 g/ml. what volume of this reagent should be diluted to 1.0
vlada-n [284]

Answer: 2.4 ml

Solution :

Molar mass of NH_3 = 17 g/mole

Given,: 28% w/w of NH_3 solution means 28 g of ammonia in 100 g of solution.

Mass of solution = 100 g

Now we have to calculate the volume of solution.

Volume=\frac{Mass}{Density}=\frac{100g}{0.899g/ml}=111.2ml  

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Molarity=\frac{n\times 1000}{V_s}

where,

n = moles of solute NH_3=\frac{\text {given mass}}{\text {molar mass}}=\frac{28}{17}=1.65moles

V_s = volume of solution in liter = 0.11 L

Now put all the given values in the formula of molarity, we get

Molarity=\frac{1.65moles}{0.11L}=15mole/L

Using molarity equation:

M_1V_1=M_2V_2

15\times V_1=0.036\times 1.0\times 10^{3}

V_1=2.4ml

6 0
3 years ago
Combustion of hydrocarbons such as undecane (C_11H_24) produces carbon dioxide, a "greenhouse gas." Greenhouse gases in the Eart
bekas [8.4K]

Answer:

Volume of carbon dioxide is 428.23 L.

Explanation:

Below is the chemical reaction or chemical equation for the combustion of hydrocarbons such as undecane into carbon dioxide.

C_{11}H_{24}(l) + 17O_{2}(g) \to 11CO_{2} (g) + 12H_2O(g)

Here, undecane is in liquid form that reacts with gaseous oxygen (combustion)  and produces carbon dioxide and water as a product in the gaseous form.

The molar mass of undecane = 156.31 g/mol.

\text{Number of moles} = \frac{260g}{156.31g/mol} = 1.66 \ mol.

From the equation, it can be seen that 1 mole of undecane produces 11 moles of carbon dioxide. Therefore, 1.66 mol will produce 18.26 mol of carbon dioxide.

Now find the volume of 18.26 mol of carbon dioxide when the temperature is 13 degrees Celsius and pressure is 1 atm.

V = \frac{nRT}{P} \\

V = \frac{18.26 \times 0.082 \times 286 \ K}{1atm} \\

V = 428.23 \ L

6 0
3 years ago
Which scientist was the first to devise the rules of chemical reactions that are explained by modern atomic theory?
valina [46]

Answer:

John Dalton is the correct answer.

Explanation:

3 0
3 years ago
The only part of Earth's inner structure that is a liquid is the _____. A. inner core B. lower mantle C. outer core D. crust
slavikrds [6]

Answer:

lower mantle

Explanation:

because the core and the crust are solid.

8 0
3 years ago
Read 2 more answers
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