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elena55 [62]
3 years ago
6

KClO₃ → Kelt Oz

Chemistry
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

5.2 moles of  KClO₃  are needed

Explanation:

Given data:

Number of moles of potassium chlorate needed = ?

Number of moles of O₂ formed = 7.8 mol

Solution:

Chemical equation:

2KClO₃      →     2KCl + 3O₂

now we will compare the moles of KClO₃ and  O₂.

                   O₂        :         KClO₃    

                    3          :           2

                   7.8        :          2/3×7.8 = 5.2

5.2 moles of  KClO₃  are needed.

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What is the percentage error of length measurement of 0.229cm if the correct value is 0.225cm
Mars2501 [29]

Percent error is the difference between the measured and known value, divided by the known value, multiplied by 100%.

So first, we take our measured value, .299 cm, minus our known value, .225 cm.

.299 cm - .225 cm=.004 cm

Next, we divide that by our known value

\frac{.004}{.225}=.0177777778

Finally, multiply your answer by 100

.0177777778 x 100= 1.77777778 %

Round to three significant figures, and you're done.

=1.78 % error



5 0
3 years ago
Read 2 more answers
Conduction happens as energy flows from a warmer object to a cooler object. Which of the following is evidence of conduction?
Dmitrij [34]

Explanation:

Conduction is a form of heat transfer between one body and another. It usually occurs when a warmer object is in contact with a cooler one. Heat generally flows from a region of high temperature to a place at a lower temperature.

  • Conduction is very pronounced in solid bodies.
  • The heat transfer causes a net transfer of the average kinetic energy of one body to the other.
  • Some examples are: heating of iron by a hotter metallic body, the pot hand getting hotter as cooking continues, cooling of ice by touching it.
8 0
3 years ago
Explain how to draw the electron-dot diagram for oxygen.
AlexFokin [52]

The electron dot diagram for the oxygen atom shows six electrons around the symbol of the atom.

<h3>What is the electron dot diagram?</h3>

The electron dot diagram is the diagram of atoms of elements showing only the valence electrons present in the atom represented with dots.

The electron dot diagram for the oxygen atom is drawn as follows:

  • The number of valence electrons in oxygen atom is determined; valence electrons = 6
  • The symbol for the oxygen atom is written
  • The valence electrons are shown as dots around the symbol of the element.

In conclusion, the electron dot diagram uses dots around the symbol of an atom to show the valence electrons in the atom.

Learn more about electron dot diagram at: brainly.com/question/5835591

#SPJ1

7 0
1 year ago
How much energy is required to raise the temperature of 10.6 grams of gaseous neon from
Alona [7]

Answer:

Approximately 1.95 \times 10^{2}\; \rm J.

Explanation:

Look up the specific heat of gaseous neon:

c = 1.03 \; \rm J \cdot g^{-1} \cdot K^{-1}.

Calculate the required temperature change:

\Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Let m denote the mass of a sample of specific heat C. Energy required to raise the temperature of this sample by \Delta T:

Q = c \cdot m \cdot \Delta T.

For the neon gas in this question:

  • c = 1.03\; \rm J \cdot g^{-1}\cdot K^{-1}.
  • m = 10.6\; \rm g.
  • \Delta T = (37.9 - 20.0)\; \rm K = 17.9\; \rm K.

Calculate the energy associated with this temperature change:

\begin{aligned}Q &= c \cdot m \cdot \Delta T \\ &= 1.03\; \rm J \cdot g^{-1}\cdot K^{-1} \times 10.6\; \rm g \times 17.9\; \rm K \\ &\approx 1.95 \times 10^{2}\; \rm J\end{aligned}.

3 0
3 years ago
Un anillo, de masa 90 gramos, contiene 59,1% de oro. ¿Cuál es el valor del anillo si cada mol de oro vale S/.1800?. Considere el
LekaFEV [45]

Answer:

S/.486 es el valor del anillo

Explanation:

Para hallar el precio del anillo se deben encontrar las moles de oro que contiene este.

Si el anillo es de 90g y solo el 59.1% contiene oro, la cantidad de oro en gramos es:

90g × 59.1% = 53.19g Oro en el anillo

Ahora, para convertir los gramos de oro a moles se debe usar la masa atómica del oro (197g/mol), así:

53.19g × (1mol / 197g) = <em><u>0.27 moles de oro contiene el anillo</u></em>.

Ya que cada mol de oro cuesta S/.1800, 0.27 moles de oro (Y por lo tanto, el anillo) costarán:

0.27mol × (S/.1800 / 1mol oro) =

<h3>S/.486 es el valor del anillo</h3>
8 0
3 years ago
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