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elena55 [62]
3 years ago
6

KClO₃ → Kelt Oz

Chemistry
1 answer:
cestrela7 [59]3 years ago
5 0

Answer:

5.2 moles of  KClO₃  are needed

Explanation:

Given data:

Number of moles of potassium chlorate needed = ?

Number of moles of O₂ formed = 7.8 mol

Solution:

Chemical equation:

2KClO₃      →     2KCl + 3O₂

now we will compare the moles of KClO₃ and  O₂.

                   O₂        :         KClO₃    

                    3          :           2

                   7.8        :          2/3×7.8 = 5.2

5.2 moles of  KClO₃  are needed.

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372 mL is the volume of Aluminum, density is 2.70 g/mL what is the mass in grams
podryga [215]

Answer:

930 g

Explanation:

D = m/V     Multiply both sides by V

m = VD

<em>Data: </em>

V = 372 cm³

D = 2.70 g/cm³

<em>Calculation: </em>

m = 372 × 2.50

m = 930 g

The mass of Al is 930 g.

7 0
3 years ago
He reaction produces 1.6 g of gas in 30 seconds.Calculate the mean rate of the reaction in the first 30 seconds.Use the equation
devlian [24]

Answer:

Mean rate of reaction produced = 0.533 g/sec (approx.)

Explanation:

Given:

Reaction produced = 1.6 gram

Time taken = 30 sec

Find:

Mean rate of reaction produced

Computation:

Mean rate of reaction produced = Reaction produced / Time taken

Mean rate of reaction produced = 1.6 / 30

Mean rate of reaction produced = 0.533 g/sec (approx.)

5 0
2 years ago
If two atoms are bonded with a bond energy of 87 kJ, what must be done to break the bond?
SSSSS [86.1K]
I would say the energy has to be decreased by 87 kj because the bonding is held together by 87 kj so removing that should prevent the bonding from taking place or reverse it I believe. In other words, a certain amount of energy is required to hold the bond together and in the absence of that energy, the bonding will not take place.
7 0
3 years ago
Help i give more point this time​
dmitriy555 [2]

Answer:

It's a type of chemical bond that emerges because of electrostatic force between electrons and positive metal charges.

Explanation:

I don't know if this is what you are looking for but i don't mind if you copy it.

3 0
2 years ago
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