Answer:
C. 0.191 M
Explanation:
Our goal for this question, is to calculate the concentration of the HCl solution. For this, in the experiment, a solution of NaOH was used to find the moles of HCl. Therefore, our first step is to know the <u>reaction between HCl and NaOH</u>:

The "<u>titrant"</u> in this case is the NaOH solution. If we know the concentration of NaOH (0.100M) and the volume of NaOH (38.2 mL=0.0382 L), we can calculate the moles using the <u>molarity equation</u>:



Now, in the reaction, we have a <u>1:1 molar ratio</u> between HCl and NaOH (1 mol of HCl is consumed for each mole of NaOH added). Therefore we will have the same amount of moles of HCl in the solution:

If we want to calculate the molarity of the HCl solution we have to <u>divide by the litters</u> of HCl used in the experiment (20 mL= 0.02 L):

The concentration of the HCl solution is 0.191 M
I hope it helps!
I think the symbol of the element is Ga sorry if I’m wrong
yes 89.75 sorry I'm not the best at math you should look on the internet
Answer:
the two spectator ions are; K(+) and NO3(-)
Explanation:
First off, let's write out the balanced chemical equation for the reaction;
3K2CO3(aq) +2Fe(NO3)3(aq) ----> 6KNO3(aq) + Fe2(CO3)3(s)
In order to identify which ions are spectators, we have to break the equation down to an ionic equation. This is done by splitting all aqueous compounds into ions while leaving the solids, liquids as they are.
We have;
K(+) + CO3(2-) + Fe(3+) + NO3(-) ---> K(+) + NO3(-) + Fe2(CO3)3(s)
Spectators ions are pretty much those ions that do not undergo a change in the reaction. Spectator ions always have the same number of moles and charge in both sides of the reaction.
Upon observing the ionic equation, we can tell that the two spectator ions are; K(+) and NO3(-)
The correct answer you are looking for is napalm
Hope this helps!