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Helen [10]
3 years ago
10

On veut comparer l’efficacité de la configuration batch avec celle du continu CSTR pour la production de 10^3 tonnes de levures

humides (90% d'eau). Si on suppose qu'on a le même volume pour les deux réacteurs,comparez les temps nécessaires pour chaque type de réacteur.Montrez tous les détails du calcul, des bilans de masses, et expliquez vos choix des paramètres cinétiques et stœchiométriques.
Chemistry
1 answer:
belka [17]3 years ago
8 0

Answer:

peux tu me donner plus de précisions stp concernant le détail de calcul que tu souhaite avoir  ?

Explanation:

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Chem help what's the answer to 8 and why will give brainliest​
laiz [17]

avogadros law states that under constant temp n pressure, volume of a gas is directly proportional to amount of gas

amount of gas1 = 352millimoles

amount of gas2 = 352+100 = 452millimoles

new vol = old vol x 452/352 = 25.2 x 452/352

= 32.4 mL

4 0
3 years ago
Read 2 more answers
If 3.6 g of aluminum completely reacts, how much Al2O3 (in grams) can be produced
marissa [1.9K]

The amount in grams of  Al₂O₃ produced is approximately 6.80 g.

Aluminium reacts completely with oxygen(air) to produce Al₂O₃. The reaction can be represented with a chemical equation as follows:

AL + O₂ → Al₂O₃

Let's balance it

4AL + 3O₂ → 2Al₂O₃

4 moles of Aluminium reacts with 3 moles of Oxygen molecules to produce 2 moles of Aluminium oxide. Therefore,

Since, aluminium reacts completely, it is the limiting reagent in the reaction. Therefore,

Atomic mass of AL = 27 g

Molar mass of  Al₂O₃ = 101.96 g/mol

4(27 g) of AL gives 2(101.96 g) of  Al₂O₃

3.6 g of AL will give ?

cross multiply

mass of  Al₂O₃ produced = 3.6 × 203.92 / 108   = 734.112 / 108 = 6.797

mass of  Al₂O₃ produced = 6.80 g.

read more: brainly.com/question/23982245?referrer=searchResults

8 0
3 years ago
A hiker has packed a bag of chips as a snack. At the start of the hike the pressure was 1.5 atm and the temperature was 35*C. At
Mazyrski [523]
According to <span>Gay-Lussac's Law the temperature and Pressure are directly proportional to each other if the amount and volume of given gas are kept constant.
Mathematically for initial and final states it is expressed as,

                                          P</span>₁ / T₁  =  P₂ / T₂     ----- (1)
Data Given;
                  P₁  =  1.5 atm

                  T₁  =  35 °C + 273  =  308 K

                  P₂  =  ?

                  T₂  =  0 °C + 273  =  273 K

Solving Eq. 1 for P₂,

                                   P₂  =  P₁ T₂ / T₁

Putting values,
                                   P₂  =  (1.5 atm × 273 K) ÷ 308 K

                                   P₂  =  1.32 atm
Result:
           As the temperature is decreased so the pressure also decreases from 1.5 atm to 1.32 atm. Therefore the bag will contract.
5 0
3 years ago
Sodium chloride is produced from its elements
Kisachek [45]

Answer:

                     Mass of Sodium  =  574.75 g

                     Mass of Chlorine  =  886.25 g

Explanation:

                   The  balance chemical equation for the synthesis of NaCl is,

                                        2 Na + Cl₂ → 2 NaCl

Step 1: <u>Find out moles of each reactant required,</u>

According to balance chemical equation,

                 2 moles of NaCl is produced by  =  2 moles of Na

So,

         25 moles of NaCl will be produced by  =  X moles of Na

Solving for X,

                     X  =  25 mol × 2 mol /  2 mol

                     X  =  25 moles of Na

Similarly for Cl₂,

According to balance chemical equation,

                 2 moles of NaCl is produced by  =  1 mole of Cl₂

So,

         25 moles of NaCl will be produced by  =  X moles of Cl₂

Solving for X,

                     X  =  25 mol × 1 mol /  2 mol

                     X  =  12.5 moles of Cl₂

Step 2: <u>Convert each moles to mass as;</u>

Mass  =  Moles × Atomic Mass

For Na,

Mass  =  25 mol × 22.99 g/mol

Mass  =  574.75 g

For Cl₂,

Mass  =  12.5 mol × 70.90 g/mol

Mass  =  886.25 g

6 0
3 years ago
15.0 moles of gas are in a 8.00 L tank at 22.3 ∘C∘C . Calculate the difference in pressure between methane and an ideal gas unde
leva [86]

Answer:

\Delta P=4.10atm

Explanation:

Hello!

In this case, since the ideal gas equation is used under the assumption of no interaction between molecules and perfectly sphere-shaped molecules but the van der Waals equation actually includes those effects, we can compute each pressure as shown below, considering the temperature in kelvins (22.3+273.15=295.45K):

P^{ideal}=\frac{nRT}{V}=\frac{15.0mol*0.08206\frac{atm*L}{mol*K}*295.45K}{8.00L}=45.5atm

Next, since the VdW equation requires the molar volume, we proceed as shown below:

v=\frac{8.00L}{15.0mol}=0.533\frac{L}{mol}

Now, we use its definition:

P^{VdW}=\frac{RT}{v-b} -\frac{a}{v^2}

Thus, by plugging in we obtain:

P^{VdW}=\frac{0.08206\frac{atm*L}{mol*K}*295.45K}{0.533mol/L-0.0430L/mol} -\frac{2.300L^2*atm/mol^2}{(0.533L/mol)^2}\\\\P^{VdW}=49.44atm-8.09atm\\\\P^{VdW}=41.4atm

Thus, the pressure difference is:

\Delta P=45.5atm-41.4atm\\\\\Delta P=4.10atm

Best regards!

6 0
3 years ago
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