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Nucleus:direct all the organelles
Answer:
Explanation:
THE QUESTION SHOULD BE
Write the equilibrium constant expression, Kc, for the following reaction: If either the numerator or denominator is 1, please enter 1 CaCO3(s).
CaCO3(s) <=> Ca2+(aq) + CO32-(aq)
Write the mathematical form of the concentration of the products, then divide it by the concentration of the reactants as follows
Kc =[Ca2+]^1 . [CO32-]^1 / [CaCO3]^1
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Answer : The activation energy for the reaction is,
Explanation :
According to the Arrhenius equation,
Taking logarithm on both side, we get:
where,
= activation energy for the reaction
R = gas constant = 8.314 J/mole.K
T = temperature
K = rate constant
A = pre-exponential factor
The linear equation expression is:
y = mx + c
Plot of ln (K) versus (1/T) gives a straight line with a slope is equal to,
As we are given that:
Slope =
So,
Thus, the activation energy for the reaction is,