Answer : The pH of the solution is, 4.9
Explanation : Given,
Dissociation constant for acetic acid = 
Concentration of acetic acid = 0.05 M
Concentration of sodium acetate = 0.075 M
First we have to calculate the value of
.
The expression used for the calculation of
is,

Now put the value of
in this expression, we get:



Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[CH_3COONa]}{[CH_3COOH]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BCH_3COONa%5D%7D%7B%5BCH_3COOH%5D%7D)
Now put all the given values in this expression, we get:


Therefore, the pH of the solution is 4.9.