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Pani-rosa [81]
3 years ago
11

A ball is thrown into the air with an upward velocity of 20 feet per second. Its height, h, in feet after t seconds is given by

the function h(t)=-16t^2+20t+2. What is the ball's maximus height? How long does it take the ball to reach its maximum height? Round to the nearest hundredth, if necessary.
A. Reaches a max height of 8.25 feet after 1.25 seconds
B. Reaches a max height of 8.25 feet after 0.63 seconds
C. Reaches a max height of 0.16 feet after 1.34 seconds
D. Reaches a max height of 0.32 feet after 1.34 seconds.
I will give medal thanks!
Physics
1 answer:
Margarita [4]3 years ago
3 0
Thank you for posting your question here at brainly. Feel free to ask more questions.  
<span>The best and most correct answer among the choices provided by the question is B. Reaches a max height of 8.25 feet after 0.63 seconds</span> .     <span><span>

</span><span>Hope my answer would be a great help for you. </span> </span>  

<span> </span>

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Determine the inductance L of a 0.65-m-long air-filled solenoid 3.2 cm in diameter containing 8400 loops.
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Answer:

The inductance is  L  = 0.1097 \ H

Explanation:

From the question we are told that

  The  length is  l  =  0.65 \ m

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    The  number of loops is  N  =  8400

Generally the radius is evaluated as

       r = \frac{ 0.032 }{2}  =  0.016 \ m

The  inductance is mathematically represented as

      L  =  \frac{ \mu_o  *  N^2  * A }{ l }

Here \mu_o is the permeability of free space with value  \mu_o   = 4\pi * 10^{-7} N/A^2

A is the cross-sectional area which is mathematically evaluated as

             A =  \pi  r^2

=>        A =  3.142 *  (0.016)^2

=>        A =  0.000804 \ m^2

 =>  L  =  \frac{   4\pi * 10^{-7} *  8400^2  * 0.000804  }{ 0.65 }

=>    L  = 0.1097 \ H

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