If you multiply m (the unit for wavelength) with 1s (the unit for frequency), you will get m/s, the unit for speed. Now multiply! 25 m/s is your final answer!
The correct answer is D. I alread took this test.
Answer:
A pure substance consisting only of atoms with the same number of protons in their nuclei-these appear on the periodic table
Oxygen
Hydrogen
Carbon
Sulfur
Phosphate
Nitrogen
Magnesium
Calcium
Potassium
Chlorine
(I know that these are more examples than needed, but you can use any)
Answer:
C. Waves transfer energy, but not matter.
Explanation: hope this helps :)
Answer:
a
![F =326.7 \ N](https://tex.z-dn.net/?f=F%20%20%3D326.7%20%5C%20N)
b
![M = 6](https://tex.z-dn.net/?f=M%20%20%3D%206)
Explanation:
From the question we are told that
The mass of the rock is ![m_r = 200 \ kg](https://tex.z-dn.net/?f=m_r%20%20%3D%20%20200%20%5C%20kg)
The length of the small object from the rock is ![d = 2 \ m](https://tex.z-dn.net/?f=d%20%20%3D%20%202%20%5C%20m)
The length of the small object from the branch ![l = 12 \ m](https://tex.z-dn.net/?f=l%20%20%3D%20%2012%20%5C%20m)
An image representing this lever set-up is shown on the first uploaded image
Here the small object acts as a fulcrum
The force exerted by the weight of the rock is mathematically evaluated as
![W = m_r * g](https://tex.z-dn.net/?f=W%20%3D%20%20m_r%20%2A%20%20g)
substituting values
![W = 200 * 9.8](https://tex.z-dn.net/?f=W%20%3D%20%20%20200%20%2A%20%209.8)
![W = 1960 \ N](https://tex.z-dn.net/?f=W%20%3D%20%20%201960%20%5C%20N)
So at equilibrium the sum of the moment about the fulcrum is mathematically represented as
![\sum M_f = F * cos \theta * l - W cos\theta * d = 0](https://tex.z-dn.net/?f=%5Csum%20%20M_f%20%20%3D%20%20F%20%2A%20cos%20%5Ctheta%20%2A%20%20l%20%20-%20%20W%20cos%5Ctheta%20%20%2A%20%20d%20%3D%20%200)
Here
is very small so
and ![cos\theta * d = d](https://tex.z-dn.net/?f=cos%5Ctheta%20%20%2A%20%20d%20%20%3D%20%20d)
Hence
![F * l - W * d = 0](https://tex.z-dn.net/?f=F%20%2A%20%20%20l%20%20-%20%20W%20%20%2A%20d%20%3D%20%200)
=> ![F = \frac{W * d}{l}](https://tex.z-dn.net/?f=F%20%20%3D%20%5Cfrac%7BW%20%2A%20d%7D%7Bl%7D)
substituting values
![F = \frac{1960 * 2}{12}](https://tex.z-dn.net/?f=F%20%20%3D%20%5Cfrac%7B1960%20%2A%20%202%7D%7B12%7D)
![F =326.7 \ N](https://tex.z-dn.net/?f=F%20%20%3D326.7%20%5C%20N)
The mechanical advantage is mathematically evaluated as
![M = \frac{W}{F}](https://tex.z-dn.net/?f=M%20%20%3D%20%5Cfrac%7BW%7D%7BF%7D)
substituting values
![M = \frac{1960}{326.7}](https://tex.z-dn.net/?f=M%20%20%3D%20%5Cfrac%7B1960%7D%7B326.7%7D)
![M = 6](https://tex.z-dn.net/?f=M%20%20%3D%206)