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Whitepunk [10]
3 years ago
5

What happens to the pressure in a tire if air is slowly leaking out of the tire? explain your answer?

Physics
1 answer:
creativ13 [48]3 years ago
3 0
It's pretty simple. When air is leaking out of a tire, like a tiny hole or something, the pressure in the tire decreases, because without air in the tire, there is no pressure.
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A 30 kg student drops down from the monkey bars. The acceleration due to gravity is -9.8 m/s^2. Neglecting air drag, what is the
Sholpan [36]

The net force on the student is A) -294 N

Explanation:

Neglecting air resistance, there is only one force acting on the student: the force of gravity, which is given by

F=mg

where

m is the mass of the student

g is the acceleration of gravity

In this problem, we have:

m = 30 kg is the mass of the student

g=-9.8 m/s^2 is the acceleration of gravity, where the negative sign means the direction is downward

Substituting, we find the force of gravity on the student:

F=(30)(-9.8)=-294 N

And since this is the only force acting on the student, it is also the net force on him.

Learn more about gravitational force:

brainly.com/question/1724648

brainly.com/question/12785992

#LearnwithBrainly

8 0
3 years ago
As you sit in a chair, in what direction (or directions) do you exert an action force?
enyata [817]
As we sit in a chair, Action force will be only in one direction and that direction would be downward only.

In short, Your Answer would be Option A

Hope this helps!
5 0
3 years ago
Read 2 more answers
Compare the maximum rate of heat transfer to the basal metabolic rate by converting a bmr of 88 kcal/hr into watts. what is the
elena-14-01-66 [18.8K]

Explanation :

It is given that,

BMR i.e basal metabolic rate is 88 kcal/hr. So, BMR in watts is converted by the following :

We know that, 1 kilocalorie = 4184 joules

So, 1\ kcal/h=\dfrac{1\times 4184\ J}{3600\ sec}

1\ kcal/h=1.16\ J/sec

J/sec is nothing but watts.

So, 1\ kcal/h=1.16\ watts

and 88\ kcal/h=88\times 1.16\ watts = 102.08\ watts

So, it can be seen that the body can accommodate a modes amount of activity in hot weather but strenuous activity would increase the metabolic rate above the body's ability to remove heat.

8 0
3 years ago
A horizontal spring is attached to a wall at one end and a mass at the other. The mass rests on a frictionless surface. You pull
LenKa [72]

Answer:

54%

Explanation:

So, we have that the "magnitude of its displacement from equilibrium is greater than (0.66)A—''. Thus, the first step to take in answering this question is to write out the equation showing the displacement in simple harmonic motion which is = A cos w×t.

Therefore, we will have two instances t the displacement that is to say at a point 2π/w - a2 and the second point at a = a2.

Let us say that 2π/w = A, then, we have that a = A cos ^-1 (0.66)/2π. Also, we have that a2 = A/2 - A cos^- (0.66) / 2π.

The next thing to do is to calculate or determine the total length of of the required time. Thus, the total length is given as:

2a1 + ( A - 2a2) = 2A{ cos^-1 (0.66)}/ π.

Therefore, the total percentage of the period does the mass lie in these regions = 100 × {2a1 + ( A - 2a2) }/A = 2 { cos^-1 (0.66)}/ π × 100 = 54%.

Thus, the total percentage of the period does the mass lie in these regions = 54%.

6 0
3 years ago
Please help me! It says on the directions to compete the covalent bonds
Alona [7]
H2 or H:H 

hope this helps 
5 0
3 years ago
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