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nika2105 [10]
2 years ago
11

HI HELP ONLY DO THE 2nd ONE!

Chemistry
2 answers:
Likurg_2 [28]2 years ago
8 0
I would say they design and build things.
Lerok [7]2 years ago
8 0
Construct and design
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Which unit conversion allows you to convert 21.0 gallons into milliliters?
Ulleksa [173]

Answer:

Explanation:

we are given

there are in 0.073 gallons

we can see that there are two non-zero places after decimals

so, there are two siginificant figures

step-1: Change gallons to quarts

we know that

1 gallon = 4 quarts

so, we can write as

step-2: Change into liter

we know that

1 liter = 1.057 quarts

or

step-3: Change into millilitre

we know that

Since, it is asking for only two significant figures

so, we can also write as

...................Answer

3 0
3 years ago
A magnet sticks to an iron can and an iron rod. This is an intrinsic property. <br> True or false?
lesantik [10]

Answer:

True

Explanation:

Well,I hope it helps....

Just correct me if I'm wrong..

8 0
3 years ago
It is found that a gas undergoes a first-order decomposition reaction. If the rate constant for this reaction is 8.1 x 10-2 /min
kap26 [50]

Answer:

28.43 min

Explanation:

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Given that:

The rate constant, k = 8.1\times 10^{-2} min⁻¹

Initial concentration [A_0] = 0.1 M

Final concentration [A_t] = 1.0\times 10^{-2} M

Time = ?

Applying in the above equation, we get that:-

1.0\times 10^{-2}=0.1e^{-8.1\times 10^{-2}\times t}

0.1e^{-8.1\times \:10^{-2}t}=10^{-2}

e^{-8.1\times \:10^{-2}t}=\frac{1}{10}

\ln \left(e^{-8.1\times \:10^{-2}t}\right)=\ln \left(\frac{1}{10}\right)

t=28.43\ min

3 0
3 years ago
Will give brainliest please help!!
amm1812

Answer:

I think it's B so maybe

3 0
3 years ago
What is the maximum number of moles of NaCl that can be produced from the reaction of 5.6 mol Na and 4.7 mol CI2?
RideAnS [48]

Answer:

Explanation:

Na + Cl2 —> NaCl

8 0
2 years ago
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