Answer:
1.67mol/L
Explanation:
Data obtained from the question include:
Mole of solute (K2CO3) = 5.51 moles
Volume of solution = 3.30 L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:
Molarity = mole of solute /Volume of solution
Molarity = 5.51 mol/3.30 L
Molarity = 1.67mol/L
Therefore, the molarity of K2CO3 is 1.67mol/L
There is one missing point in the question.
The formula to find an increase in boiling Temperature is :
ΔT = kb x M
ΔT = is the increase in boiling Temperature
Kb = Boiling point constant of the Solvent
M = Molarity
You did not provide the Kb. If you have it, you just have to insert it to the formula to find the ΔT.
And assuming that the other solution is water, you just have to add it up with 100 Celcius
Answer:
Assuming pressure is held constant,the question reduces to a ratio and proportion type of question where;
At constant pressure,
21.0ft³-55.0°F
11.0fy³=11.0ft³/21.0ft³×55°F
The temperature is 28.809°F≈29°F
Answer:
C. 0.001 second
Explanation:
Millisecond is a subunit of a second.
Milli depicts a unit to the power of 10⁻³
So;
1 millisecond = 10⁻³ s
Therefore,
1 x 10⁻³ = 0.001s
The solution to this problem is choice C which is 0.001 second
