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leonid [27]
2 years ago
5

The mean absolute deviation tells you how spread out or how clustered around the mean a set of data is. This is the variation in

the data. To compare sets, a higher mean absolute deviation indicates that the data points are more spread out from the mean. A lower mean absolute deviation indicates dat
Mathematics
2 answers:
jonny [76]2 years ago
6 0

Answer:

hes right ↑

Step-by-step explanation:

tamaranim1 [39]2 years ago
4 0

Answer:

data points or values are nearer to the mean

Step-by-step explanation:

Given that mean absolute deviation tells you how to spread out or how clustered around the mean a set of data is.

Hence, in a comparison of sets, a higher mean absolute deviation indicates that the data points are more spread out from the mean.

On the other hand, a lower mean absolute deviation indicates that the data points are nearer to the mean than a data set with a higher mean absolute deviation

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Equivalent expression
Nataly_w [17]
7(x+8) could work for that
8 0
2 years ago
Round 0.687 yo the nearest tenths place
Vaselesa [24]

Answer: 0.7

Locate the tenths place which is just to the right of the decimal point. We see a 6 in this spot. Just to the right of this 6 is the value 8. Since 8 is larger than 5, we bump the 6 up to 7 and erase everything else to the right. You can think of it like this

0.687 ---> 0.6 which bumps up to 0.7

This is like saying 687 is closer to 700 than it is to 600

4 0
2 years ago
Please help with any of this Im stuck and having trouble with pre calc is it basic triogmetric identities using quotient and rec
german

How I was taught all of these problems is in terms of r, x, and y. Where sin = y/r, cos = x/r, tan = y/x, csc = r/y, sec = r/x, cot = x/y. That is how I will designate all of the specific pieces in each problem.

#3

Let's start with sin here. \frac{2\sqrt{5}}{5} = \frac{2}{\sqrt{5}} Therefore, because sin is y/r, r = \sqrt{5} and y = +2. Moving over to cot, which is x/y, x = -1, and y = 2. We know y has to be positive because it is positive in our given value of sin. Now, to find cos, we have to do x/r.

cos = \frac{-1}{\sqrt{5}} = \frac{-\sqrt{5}}{5}

#4

Let's start with secant here. Secant is r/x, where r (the length value/hypotenuse) cannot be negative. So, r = 9 and x = -7. Moving over to tan, x must still equal -7, and y = 4\sqrt{2}. Now, to find csc, we have to do r/y.

csc = \frac{9}{4\sqrt{2}} = \frac{9\sqrt{2}}{8}

The pythagorean identities are

sin^2 + cos^2 = 1,

1 + cot^2 = csc^2,

tan^2 + 1 = sec^2.

#5

Let's take a look at the information given here. We know that cos = -3/4, and sin (the y value), must be greater than 0. To find sin, we can use the first pythagorean identity.

sin^2 + (-3/4)^2 = 1

sin^2 + 9/16 = 1

sin^2 = 7/16

sin = \sqrt{7/16} = \frac{\sqrt{7}}{4}

Now to find tan using a pythagorean identity, we'll first need to find sec. sec is the inverse/reciprocal of cos, so therefore sec = -4/3. Now, we can use the third trigonometric identity to find tan, just as we did for sin. And, since we know that our y value is positive, and our x value is negative, tan will be negative.

tan^2 + 1 = (-4/3)^2

tan^2 + 1 = 16/9

tan^2 = 7/9

tan = -\sqrt{7/9} = \frac{-\sqrt{7}}{3}

#6

Let's take a look at the information given here. If we know that csc is negative, then our y value must also be negative (r will never be negative). So, if cot must be positive, then our x value must also be negative (a negative divided by a negative makes a positive). Let's use the second pythagorean identity to solve for cot.

1 + cot^2 = (\frac{-\sqrt{6}}{2})^{2}

1 + cot^2 = 6/4

cot^2 = 2/4

cot = \frac{\sqrt{2}}{2}

tan = \sqrt{2}

Next, we can use the third trigonometric identity to solve for sec. Remember that we can get tan from cot, and cos from sec. And, from what we determined in the beginning, sec/cos will be negative.

(\frac{2}{\sqrt{2}})^2 + 1 = sec^2

4/2 + 1 = sec^2

2 + 1 = sec^2

sec^2 = 3

sec = -\sqrt{3}

cos = \frac{-\sqrt{3}}{3}

Hope this helps!! :)

3 0
2 years ago
Read 2 more answers
Solve the math problem
Korvikt [17]

Answer:

3=-8y+5

Step-by-step explanation:

Gather your like terms, - 3y and - 5y which in turn in - 8y. You cant plus by 5 as it is not a like term. IF we were finding y we would rearrange and bring +5 to the other side and so on...

7 0
2 years ago
Given: AB ∩ CD ∩ GF = O, E ∈ interior of ∠GOB, H ∈ interior of ∠AOF. Without changing the picture indicate: Vertical angle to ∠G
lys-0071 [83]

Answer:

The verticle angle to GOB is AOF.

Step-by-step explanation:

Look at the picture, it's pretty clear

5 0
3 years ago
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