Answer:
the lowest passing score would be x = 298
Step-by-step explanation:
School wishes that only 2.5 percent of students taking test pass
We are given
mean= 200,
standard deviation = 50
We need to find x
The area under the curve can be found by:
2.5 % = 0.025
So, 1- 0.025 = 0.975
We need to find the value of z for which the answer is 0.975
Looking at the z-score table, the value of z is: 1.96
Now, using the formula:
z = x - mean/standard deviation
1.96 = x - 200/50
=> 1.96 * 50 = x-200
98 = x - 200
=> x = 200+98
x = 298
So, the lowest passing score would be x = 298
4b²+20b+25=0
Divide everything by 4
b²+5b+ 6.25=0
use the quadratic formula
x= (-b+ or - √b²-4ac) /2a
x= (-5 + or - √5²-4*1*6.25) /2(1)
x= -5/2 so
in this case, b= -5/2
Answer:
7.625
Step-by-step explanation:
This would be written like this bc to 3 decimal places its 5.You then round 4 up to 5,because the third decimal place is higher than 4.
The answer of the next term is 31
