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Scorpion4ik [409]
3 years ago
8

7 ( x + 4 ) 2 − 3 x when x = 2 ?

Mathematics
1 answer:
PIT_PIT [208]3 years ago
4 0

Answer:

78

Step-by-step explanation:

7(x+4)2-3x=

(7x+28) x 2-3x=

(14+28) x 2-3x=

42 x 2-3x=

42 x 2-6=

84-6=

78

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Consider the following equation of the form dy/dt = f(y)dy/dt = ey − 1, −[infinity] < y0 < [infinity](a) Sketch the graph
kotegsom [21]

Complete Question:

The complete question is shown on the first uploaded image

Answer:

a) The graph of  f(y) versus y. is shown on the second uploaded image

b) The critical point is at y = 0  and the solution is asymptotically unstable.

c)The phase line is shown on the third uploaded image

d) The sketch for the several graphs of solution in the ty-plane  is shown on the fourth uploaded image

Step-by-step explanation:

Step One: Sketch The Graph of  f(y) versus y

Looking at the given differential equation

       \frac{dy}{dt} = e^{y} - 1 for -∞ < y_{o} < ∞

 We can say let \frac{dy}{dt} = f(y) =e^{y} - 1

Now the dependent value is f(y) and the independent value is y so to sketch is graph we can assume a scale in this case i cm on the graph is equal to 2 unit for both f(y) and y and the match the coordinates and after that join the point to form the graph as shown on the uploaded image.

Step Two : Determine the critical point

   To fin the critical point we have to set   \frac{dy}{dt} = 0

       This means e^{y} - 1 = 0

                          For this to be possible e^{y} = 1

                          which means that  e^{y} = e^{0}

                          which implies that y = 0

Hence the critical point occurs at y = 0

meaning that the equilibrium solution is y = 0

As t → ∞, our curve is going to move away from y = 0  hence it is asymptotically unstable.

Step Three : Draw the Phase lines

A phase line can be defined as an image that shows or represents the way an ODE(ordinary differential equation ) that does not explicitly depend on the independent variable behaves in a single variable. To draw this phase line , draw the y-axis as a vertical line and mark on it the equilibrium, i.e. where  f(y) = 0.

In each of the intervals bounded  by the equilibrium draw an upward

pointing arrow if f(y) > 0 and a downward pointing arrow if f(y) < 0.

      This phase line would solely depend on y does not matter what t is

On the positive x axis it would get steeper very quickly as you move up (looking at the part A graph).

For  below the x-axis which stable (looking at the part a graph) we are still going to have negative slope but they are going to be close to 0 and they would take a little bit longer to get steeper  

Step Four : Draw a Solution Curve

A solution curve is a curve that shows the solution of a DE (deferential equation)

Here the solution curve would be drawn on the ty-plane

So the t-axis(x-axis) is its the equilibrium  that is it is the solution

If we are above the x-axis it is going to increase faster and if we are below it is going to decrease but it would be slower (looking at part A graph)

5 0
3 years ago
Find the domain of each function f(x)=1/x
Tasya [4]

Answer:

Domain is all the possible x-values that can be plugged in and range is all the possible y-values that can be outputs. f(x)=1x can have any number as an input except for zero. If we plug in zero for x , then we would be dividing by zero which is impossible. Thus the domain is all real numbers except for zero.

Step-by-step explanation:

6 0
3 years ago
The amounts a soft drink machine is designed to dispense for each drink are normally​ distributed, with a mean of 11.711.7 fluid
dexar [7]

Answer:  0.1499

Step-by-step explanation:

Given : The amounts a soft drink machine is designed to dispense for each drink are normally​ distributed, with mean \mu=11.7\text{ fluid ounces}

Standard deviation : \sigma=0.2\text{ days}

z-score : z=\dfrac{X-\mu}{\sigma}

For X = 11.5  

z=\dfrac{11.5-11.7}{0.2}\approx-1

For X = 11.6  

z=\dfrac{11.6-11.7}{0.2}\approx-0.5

Now, the probability that the drink is between 11.511.5 and 11.611.6 fluid ounces will be :-

P(11.5

Hence, the probability that the drink is between 11.511.5 and 11.611.6 fluid ounces =0.1499

5 0
4 years ago
Anyone good at explaining surface area and volume in 9th grade geometry ?
mario62 [17]
I hope this helps. In in 7th grade, but this is what I think would help! The volume of a rectangular prism equation is vplume =length × width × height. Or volume = area of the base (B) × height. That is volume. Surface area is Surface Area = LW×LW×LH×LH×HW×HW. That is for a rectangular prism.
4 0
3 years ago
sheldon bought 4 1/2 kg of plant food. he uses 1 2/3 kg on his strawberry plant and used 1/4 kg for his tomato plant. how many k
fenix001 [56]

Answer:

Sheldon have left 2\frac{7}{12}\ kg of food.

Step-by-step explanation:

Quantity of food = 4\frac{1}{2}=\frac{9}{2} kg

Quantity used on strawberry plant = 1\frac{2}{3} = \frac{5}{3}\ kg

Quantity used on tomato plant = \frac{1}{4}\ kg

Food left = Total - used on strawberry - used on tomato

Food left = \frac{9}{2}-\frac{5}{3}-\frac{1}{4}

Food left = \frac{54-20-3}{12} = \frac{31}{12}

Food left = 2\frac{7}{12}\ kg

Therefore,

Sheldon have left 2\frac{7}{12}\ kg of food.

4 0
3 years ago
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