Answer:
b
Explanation:
because it fly and you need for it to drop at the right spot for them to get it
Answer:
a = 1.16 m/s²
Explanation:
In order to find the acceleration of the ball we will use 3rd equation of motion.
2as = Vf² - Vi²
where,
a = acceleration = ?
s = displacement = 21.9 m
Vf = Final Velocity = 7.14 m/s
Vi = Initial Velocity = 0 m/s (Since, ball starts from rest)
Therefore, using the values, we get:
2a(21.9 m) = (7.14 m/s)² - (0 m/s)²
a = (50.97 m²/s²)/(43.8 m)
<u>a = 1.16 m/s²</u>
Answer: F = 0.17N
Explanation: From the Newton second law of motion.
F= m(v-u)/t.
V=180km/hr = 180×1000/3600= 50m/s
U= 160km/hr = 160×1000/3600= 44.44m/s
t= 5secs
F=m(v-u)/t
F= 0.150(50-44.44)/5
F=0.150×5.56/5
F= 0.835/5
F= 0.17N rounded to two decimal places.
Answer:
c) 22,920 years
Explanation:
The half-life of C-14 is 5730 so in 5730 years , amount of C-14 is reduced to half.
In 5730 x 2 years , the amount of C-14 is reduced to 1/4 .
In 5730 x 3 years , the amount of C-14 is reduced to 1/8 .
In 5730 x 4 years , the amount of C-14 is reduced to 1/16 .
In 22920 years , the amount of C-14 is reduced to 1/16 .
So the answer is 22920 years.
Answer:
20000N
Explanation:
Given parameters:
Acceleration = 4m/s²
Mass of truck = 5000kg
Unknown:
Net force require to accelerate the truck = ?
Solution:
From Newton's second law of motion:
Force = mass x acceleration
So;
Force = 5000 x 4 = 20000N