A ball rolling down a hill was displaced 21.9 m while uniformly accelerating from rest. If the final velocity was 7.14 m/s, what
1 answer:
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After the ball leaves the woman's hand, the only relevant force acting on the ball is the gravity, which produces an acceleration of a=g=9.81 m/s^2 on the baseball, directed downward.
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is
at every point of the motion, and therefore also when the baseball is at its highest point.
Gravity acts on the ball for the whole duration of the motion, so the acceleration of the ball is
Answer:
- zero
Explanation:
is the magnetic quantum number.
The only possible value for the magnetic quantum number for an electron in an s orbital is 0.
The first three quantun numbers are:
- n: principal quantum number. It may have positive integer values: 1, 2, 3, 4,5, 6, 7, ...
: Azimuthal or angular momentum quantum number. It may have integer values from 0 to n - 1.
This quantum number is related to the type (or shape) of the orbital:
For s orbitals
For p orbitals
For d orbitals
For f orbitals
In this case, it is an s orbital, so we have .
, the third quantum number can have integer values
to
Since, for the s orbitals , the only possible value for
is zero.