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egoroff_w [7]
3 years ago
15

Suppose I have a spherical insulating shell with inner radius r and outer radius R. The shell has a uniformly distributed charge

of +Q. What is the charge density on my shell? 3Q / 4pi (R^3) 3Q / 4 pi (R^3 - r^3) 3Q / 4 pi (r^3 - R^3) 3Q / 4 pi (r^3) [5 points] Suppose I have a conducting sphere of radius R. I place a net charge of +Q on the sphere. What is the charge density inside the sphere? Zero
Physics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

3Q / 4 pi (R^3 - r^3)

Explanation:

Charge density = charge / volume

volume of a spherical shell = \frac{4}{3} \pi(R^{3} - r^{3})

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makkiz [27]

Answer:

They move outwards.

They don't intersect each other at any point.

They show the electric field.

Explanation:

8 0
3 years ago
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Calculate the Force of Gravity acting on an object that has a mass of 1.3 kg. The object is on Earth so use 9.8m/s2 for the acce
sweet-ann [11.9K]
To calculate the gravitational force acting on an object given the mass and the acceleration due to gravity, use the following formula.

Fg = m • g
Fg = 1.3 kg • 9.8 m/s^2
Fg = 12.74 N or about 12.7 N.

The solution is C. 12.7 N.
7 0
2 years ago
How do I write an essay on how I feel about online school​
vlabodo [156]

Answer:

Some students appreciated the social aspect of Zoom classrooms, while others felt online education worked best for them when they were working on their own. ... Students said they appreciated having a well-planned work week and didn't appreciate “surprise” assignments online any more than they appreciate them in class

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5 0
3 years ago
A 13,000-N vehicle is to be lifted by a 25-cm diameter hydraulic piston. What force needs to be applied to a 5.0 cm diameter pis
MaRussiya [10]

Answer:

Explanation:

We shall apply Pascal's Law in fluid mechanics

According to it , pressure is transmitted in liquid from one point to another without any change .

25 cm diameter = 12.5 x 10⁻² m radius

Area = 3.14 x (12.5 x 10⁻²)²

= 490.625 x 10⁻⁴ m²

Pressure by vehicle

Force / area

13000 / 490.625 x 10⁻⁴

= 26.497 x 10⁴ Pa

5 cm diameter = 2.5 x 10⁻² radius

area = 3.14 x (2.5 x 10⁻²)²

= 19.625 x 10⁻⁴ m²

If we assume required force F on this area

Pressure = F / 19.625 x 10⁻⁴ Pa

According to Pascal Law

F / 19.625 x 10⁻⁴  = 26.497 x 10⁴

F = 19.625 x 26.497

= 520 N

4 0
3 years ago
Which of the following describe circumstances under which an exculpatory clause is generally unenforceable? Select all that appl
Sveta_85 [38]

Answer:

a. When the parties have unequal bargaining power  

c. When it covers public transportation  

Explanation:

Exculpatory clauses are often found in agreements between a company and a consumer when the activity is in danger, such as at a fitness center or ski resort. The company wants the consumer to understand the risk involved and to avoid lawsuits, so it includes a disclaimer in its contract. These clauses are used to limit liability, so they are not enforced when the parties have unequal bargaining power and when covering public transport.

6 0
3 years ago
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