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egoroff_w [7]
3 years ago
15

Suppose I have a spherical insulating shell with inner radius r and outer radius R. The shell has a uniformly distributed charge

of +Q. What is the charge density on my shell? 3Q / 4pi (R^3) 3Q / 4 pi (R^3 - r^3) 3Q / 4 pi (r^3 - R^3) 3Q / 4 pi (r^3) [5 points] Suppose I have a conducting sphere of radius R. I place a net charge of +Q on the sphere. What is the charge density inside the sphere? Zero
Physics
1 answer:
a_sh-v [17]3 years ago
4 0

Answer:

3Q / 4 pi (R^3 - r^3)

Explanation:

Charge density = charge / volume

volume of a spherical shell = \frac{4}{3} \pi(R^{3} - r^{3})

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4. What's the voltage drop if V, = 56 V, V2 = 35 V, and V3 = 3 V
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The correct option is A. 18 V

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V_{1}=18\ V

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