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kupik [55]
3 years ago
14

What’s the formula for barium chloride?

Physics
2 answers:
Orlov [11]3 years ago
8 0

Answer:


BaCl2

Explanation:


Barium is listed under Group 2A of the Periodic Table. Looking at the column, Barium is Ba. The elements listed in Group 2A have a charge of +2.


So we have Barium as Ba+2


Now let's move to Chloride. Don't bother looking at the table, because it is not listed. Chloride is an ion of Chlorine, which is from Group 7A and we know anything in that column has a charge of -1. So Chlorine has gained an electron and becomes Chloride. Note that this is an anion and has a negative charge. You can see how easy it was to change the name, you just change the suffix to -ide.


So we have Chloride as Cl−


We're not finished though! The charges do not balance!


To balance it we simply add another Chloride so that you have two negatives balancing the two positives. You'll write it as Cl2.


Now they balance; you have one barium Ba+2 and two chloride Cl− Cl−


The final formula is written as BaCl2.


Hope that helps!


tensa zangetsu [6.8K]3 years ago
4 0

BaCl₂ It is one of the most common water-soluble salts of barium. Like most other barium salts, it is white, toxic, and imparts a yellow-green coloration to a flame.



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goldenfox [79]

Answer:

100Ns

Explanation:

find velocity and then plug into momentum formula momentum=(velocity)(mass)

4 0
3 years ago
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dexar [7]

1) Frequency: 7.06\cdot 10^{14} Hz

The frequency of electromagnetic radiation is given by:

f=\frac{c}{\lambda}

where

c = 3 \cdot 10^8 m/s is the speed of light

\lambda is the wavelength

In this case, the wavelength of the radiation is

\lambda=425 nm=425\cdot 10^{-9} m

Therefore the frequency is

f=\frac{3\cdot 10^8 m/s}{425 \cdot 10^{-9} m}=7.06\cdot 10^{14} Hz


2) Period: 1.42\cdot 10^{-15} s

The period is equal to the reciprocal of the frequency of the wave:

T=\frac{1}{f}

Using the frequency we found previously, f=7.06\cdot 10^{14} Hz, we find:

T=\frac{1}{7.06\cdot 10^{14} Hz}=1.42\cdot 10^{-15} s


5 0
3 years ago
A concentrated vertical laod of 6000 lbf is applied at the ground suface most nearly what is the increase in the vertical pressu
drek231 [11]

Answer:

the correct answer is option A

Explanation:

given,

Load = 6000 lbf            

depth = 3.5 ft                                      

distance from the load = 4 ft                  

vertical stress = \dfrac{3Pz^3}{2\pi (r^2+z^2)^{\frac{5}{2}}}

                        = \dfrac{3\times 6000\times 3.5^3}{2\pi (4^2+3.5^2)^{\frac{5}{2}}}

                        = 28.96 lbf/ft²                      

                        = 29 lbf/ft²              

hence, the correct answer is option A

5 0
3 years ago
The flow rate of a liquid through a 2.0 cm radius pipe is 0.008 m3 /s. the average fluid velocity in the pipe is:
Degger [83]

The average fluid velocity in the pipe can be obtained by dividing the flow rate of the liquid by the cross-sectional area of the pipe.

Av velocity = Flow rate/Cross-sectional area

Given, flow rate of the liquid = 0.008 m³/s

Cross-sectional area = \pi Radius^{2} , radius of the pipe is 0.02 m.

Substituting the values we get,

Av velocity= \frac{0.008}{\frac{22}{7}*(0.02)^{2}}

= 6.36 m/s

Average velocity of the fluid is 6.36 m/s.

6 0
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How fast would a car have to round 85 m -radius turn for its acceleration to be numerically equal to that of gravity?
Temka [501]

Answer:

A car would need to be moving with a velocity of 28.86 m/s for its acceleration to be numerically equal to the acceleration due to gravity.

Explanation:

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α = g = 9.8 m/s²

v = ?

r = 85 m

9.8 = v²/85

v² = 9.8 × 85 = 833

v = 28.86 m/s

8 0
3 years ago
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