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rjkz [21]
3 years ago
8

Match the term with its description. (4 points)

Chemistry
1 answer:
Ne4ueva [31]3 years ago
3 0

Answer:

A. a

B. c

C. b

D. d

Explanation:

You might be interested in
BALANCE THIS EQUATION:<br> C4H10 + O2 = C02 + H20
Lostsunrise [7]

Answer:

{ \rm{C _{4} H_{10}+  \frac{13}{2} O _{2} = 4C0 _{2} + 5H _{2}0}} \\

5 0
3 years ago
How does changing the temperature affect the chemical reaction?
Rufina [12.5K]

Answer:

C

Explanation:

Temperature is directly related to kinetic energy (KE). As we raise temperature, we are raising KE, as well. Particles with more KE move more quickly and with more force.

This means that these particles are more likely to collide with each other and react to allow the chemical reaction to follow through. In turn, if the chemical reaction is more likely to go to completion, the reaction rate increases, eliminating A and B.

The concentration of the solute is not affected by the temperature; in other words, temperature will not increase or decrease the amount of solute in the solution, so eliminate D.

Thus the answer is C.

Hope this helps!

4 0
3 years ago
How does upwelling affect coastal fisheries?<br> look atthe pic
djverab [1.8K]
I believe the answer is D because warm water generally has more nutrients than cold water. 

It does not improve the nutrients so it isn't B or C.

Hope this helps!
7 0
3 years ago
Read 2 more answers
Kathleen makes iced coffee by adding ice to her room temperature coffee in a glass. What statement explains what is taking place
Ganezh [65]

Answer:

The answer is the heat is transferred from the ice to the coffee.

Explanation:

Hot molecules tend to transfer to colder molcules, which causes the ice to melt and makes the coffee colder.

Hope this helps! :)

3 0
2 years ago
The reaction for the formation of gaseous hydrogen fluoride (HF) from molecular hydrogen (H2) and fluorine (F2) has an equilibri
mestny [16]

Answer:

[H2]eq = 0.0129 M

[F2]eq = 1.0129 M

[HF]eq = 0.9871 M

Explanation:

  • H2(g) + F2(g) ↔ 2HF(g)

∴ Ke = [HF]² / [H2]*[F2] = 1.15 E2

experiment:

∴ n H2 = 3.00 mol

∴ n F2 = 6.00 mol

∴ V sln = 3.00 L

⇒ [H2]i = 3.00 mol / 3.00 L = 1 M

⇒ [F2]i = 6.00 mol / 3.00 L = 2 M

        [ ]i    change      [ ]eq

H2     1         1 - x         1 - x

F2     2        2 - x         2 - x

HF     -            x              x

⇒ K = (x)² / (1 - x)*(2 - x) = 1.15 E2

⇒ x² / (2 - 3x + x²) = 1.15 E2 = 115

⇒ x² = (2 - 3x + x²)(115)

⇒ x² = 230 - 345x + 115x²

⇒ 0 = 230 - 345x + 114x²

⇒ x = 0.9871

equilibrium:

⇒ [H2] = 1 - x = 1 - 0.9871 = 0.0129 M

⇒ [F2] = 2 - x = 2 - 0.9871 = 1.0129 M

⇒ [HF] = x = 0.9871 M

5 0
3 years ago
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