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Sav [38]
3 years ago
8

From which layer of the atmosphere is between the mesosphere and the exosphere

Chemistry
1 answer:
Lesechka [4]3 years ago
8 0
The correct answer would be : thermosphere

I hope that this helps you !
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Basic atomic structure of argon​
kompoz [17]

Answer:

structure of argon

Explanation:

The nucleus contains 18 protons ( red) and 22 neutrons (orange). 18 electrons (white) occupy shells ring.

4 0
3 years ago
Which of the following metals would be the best for the new frying pan?
Rudik [331]

Answer:

Copper

Explanation:

hope this helps!

7 0
4 years ago
a scientist uses 68 grams of CaCo3 to prepare 1.5 liters of solution. what is the molarity of this solution?
victus00 [196]

Answer: 0.4533mol/L

Explanation:

Molar Mass of CaCO3 = 40+12+(16x3) = 40+12+48 = 100g/mol

68g of CaCO3 dissolves in 1.5L of solution.

Xg of CaCO3 will dissolve in 1L i.e

Xg of CaCO3 = 68/1.5 = 45.33g/L

Molarity = Mass conc.(g/L) / molar Mass

Molarity = 45.33/100 = 0.4533mol/L

7 0
4 years ago
Sometimes the color of an animal closely resembles the color of its environment. Which of the following is the most likely reaso
Deffense [45]

Answer:

The answer is D

Explanation:

Animals add color to their environment so a mate can see how creative the animal is.

6 0
3 years ago
Read 2 more answers
A 45ml of a 4M solution of CaBr2 contains how many grams of CaBr2?
natta225 [31]

The required mass of calcium bromide is 35.98 grams.

<h3>What is molarity?</h3>

Molarity is any solution is define as the number of moles of solute present in per liter of solution as;

M = n/V, where

  • M = molarity = 4M
  • V = volume = 45mL = 0.045L

Moles will be calculated by using the above equation as:

n = (4)(0.045) = 0.18 mole

Relation between the mass and moles of any substance will be represented as:

n = W/M, where

  • W = given mass
  • M = molar mass

Mass of CaBr₂ = (0.18mol)(199.89g/mol) = 35.98g

Hence required mass of CaBr₂ is 35.98 grams.

To know more about molarity, visit the below link:
brainly.com/question/22283918

#SPJ1

6 0
2 years ago
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