Answer: The value of the equilibrium constant Kc for this reaction is 0.088
Explanation:
where,
x = given mass
M = molar mass
= volume of solution in L
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
Equilibrium concentration of 
= 
The given balanced equilibrium reaction is,
The expression for equilibrium constant for this reaction will be,
![K_c=\frac{[CaO]\times [CO_2]}{[CaCO_3]}](https://tex.z-dn.net/?f=K_c%3D%5Cfrac%7B%5BCaO%5D%5Ctimes%20%5BCO_2%5D%7D%7B%5BCaCO_3%5D%7D)
Now put all the given values in this expression, we get :
Answer:
204.8g
Explanation:
The number of moles of a substance is related to its mass and molecular mass as follows:
mole (n) = mass (m) ÷ molar mass (MM)
According to this question, 3.50 moles of sodium chloride (NaCl) is added to a food.
Molar mass of NaCl = 23 + 35.5
= 58.5g/mol
Using mole = mass/molar mass
Mass = molar mass × mole
Mass = 58.5g/mol × 3.5mol
Mass = 204.75
Mass = 204.8grams.
Therefore, 204.8grams of NaCl or common salt was added to the food.
Answer:
I think it is option (b) river
The Lewis structure of Carbonic Acid (H₂CO₃) is given below. In structure it is shown that carbon has a double bond with one oxygen atom and two single bonds with hydroxyl groups.
Formal Charge; Formal charge is caculated as,
Formal charge = # of valence e⁻ - [# of lone pair of e⁻ + 1/2 # of bonded e⁻]
Formal charge on Carbon;Formal charge = 4 - [ 0 + 8/2]
Formal charge = 4 - [4]
Formal charge = Zero
