Answer:
K = 13448.64eV
Explanation:
(a) In order to calculate the kinetic energy of the electrons, to "see" the atom, you take into account that the wavelength of the electrons must be of the order of the resolution required (0.010nm).
Then, you first calculate, by using the Broglies' relation, the momentum of the electron associated to a wavelength of 0.010nm:
(1)
p: momentum of the electron
h: Planck's constant = 6.626*10^-34 Js
λ: wavelength = 0.010nm
You replace the values of the parameters in the equation (1):
With this values of the momentum of the electron you can calculate the kinetic energy of the electron by using the following formula:
(2)
m: mass of the electron = 9.1*10^-31 kg
In electron volts you obtain:
The kinetic energy required for the electrons must be, at least, of 13448.64 eV
Answer:
Mass.
Explanation:
I took the quiz and got the answer right
B = magnetic field in the cyclotron = 0.400 T
q = magnitude of charge on a proton = 1.6 x 10⁻¹⁹ C
m = mass of the proton = 1.67 x 10⁻²⁷ kg
f = frequency of revolution of proton in the cyclotron = ?
v = speed of electromagnetic waves = 3 x 10⁸ m/s
λ = wavelength of electromagnetic wave = ?
Frequency of revolution of proton in the cyclotron is given as
f = qB/(2πm)
inserting the values
f = (1.6 x 10⁻¹⁹)(0.400)/(2 (3.14) (1.67 x 10⁻²⁷))
f = 6.1 x 10⁶ Hz
wavelength of electromagnetic wave is given as
λ = v/f
λ = (3 x 10⁸)/(6.1 x 10⁶)
λ = 49.2 m
Answer:
From this equation, it can be said that the escape velocity depends on the radius of the planet and the mass of the planet only and not on the mass of the body. Escape Velocity of Earth= 11.2 km/s. This was the derivation of the escape velocity of earth or any other planet.
Explanation:
