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alexira [117]
3 years ago
11

A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m ​ 9, point, 0, start fraction, start text, m, end text, div

ided by, start text, s, end text, end fraction with 23,000\,\text J23,000J23, comma, 000, start text, J, end text of kinetic energy. What is the bear’s mass?

Physics
2 answers:
KengaRu [80]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

kolezko [41]3 years ago
3 0

Answer:

m =  0.5679 Kg

Explanation:

Given

v = 9 m/s

K = 23 KJ

m = ?

We apply the equation

K = 0.5*m*v²   ⇒   m = 2*K/v²

⇒   m = 2*23000 J/(9 m/s)² = 567,9 Kg

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Elodia [21]

Answer:

Explanation:

You are looking for the resistance to start with

W = E * E/R

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Now let's see what happens when you try putting this into 110

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W = 18.75

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18.75 / 75 = 0.25

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Answer:

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