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alexira [117]
3 years ago
11

A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m ​ 9, point, 0, start fraction, start text, m, end text, div

ided by, start text, s, end text, end fraction with 23,000\,\text J23,000J23, comma, 000, start text, J, end text of kinetic energy. What is the bear’s mass?

Physics
2 answers:
KengaRu [80]3 years ago
7 0

Explanation:

Below is an attachment containing the solution.

kolezko [41]3 years ago
3 0

Answer:

m =  0.5679 Kg

Explanation:

Given

v = 9 m/s

K = 23 KJ

m = ?

We apply the equation

K = 0.5*m*v²   ⇒   m = 2*K/v²

⇒   m = 2*23000 J/(9 m/s)² = 567,9 Kg

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B

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True or False: As distance between 2 objects increases, the gravitational force decreases
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A piece of wire 29 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
skelet666 [1.2K]

Answer:

Explanation:

Total length of the wire is 29 m.

Let the length of one piece is d and of another piece is 29 - d.

Let d is used to make a square.

And 29 - d is used to make an equilateral triangle.

(a)

Area of square = d²

Area of equilateral triangle = √3(29 - d)²/4

Total area,

A = d^{2}+\frac{\sqrt3}{4}\left ( 29-d \right )^{2}

Differentiate both sides with respect to d.

\frac{dA}{dt}=2d- \frac{\sqrt3}{4}\times 2(29-d)

For maxima and minima, dA/dt = 0

d = 8.76 m

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\frac{d^{2}A}{dt^{2}}= + ve

(a) So, the area is maximum when the side of square is 29 m

(b) so, the area is minimum when the side of square is 8.76 m

8 0
2 years ago
10. Hamilton How long does it take Lewis travelling at 156 m.p.h to cover 16 miles?
Anvisha [2.4K]

Answer: Hello!

Lewis is travelling at 165 mph, which means miles per hour, this says that he does 165 miles in one hour.

We want to know how much time takes to cover 16 miles.

this can be calculated as the quotient of the distance and the velocity; this is:

t = \frac{16 mi}{165 mi/h} = 0.096 h

if we want to write this in minutes, then:

we know that one hour has 60 minutes, then 0.096 hours has:

0.096h*60mins/1h = 5.8 minutes.

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6 0
3 years ago
Read 2 more answers
A convex security mirror has a radius of curvature of 12.0 cm. What is the magnification of a pare 3.0 m from the mirror?
Makovka662 [10]

Answer:

magnification will be -0.025

Explanation:

We have given the radius of curvature = 12 cm

And object distance = 3 m

So focal length f=\frac{R}{2}=\frac{12}{2}=6cm

Now for mirror we know that \frac{1}{f}=\frac{1}{u}+\frac{1}{v}

So \frac{1}{0.06}=\frac{1}{3}+\frac{1}{v}

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Now magnification of the mirror is m=\frac{-v}{u}=\frac{-0.750}{3}=-0.025

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3 years ago
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