A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m 9, point, 0, start fraction, start text, m, end text, div

Question

2 years ago

11

A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m 9, point, 0, start fraction, start text, m, end text, div

ided by, start text, s, end text, end fraction with 23,000\,\text J23,000J23, comma, 000, start text, J, end text of kinetic energy. What is the bear’s mass?

Physics

2 answers:

KengaRu [80] · Answer 1 · 2022-04-29T00:07:13+03:00

KengaRu [80]2 years ago

7 0

Explanation:

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kolezko [41] · Answer 2 · 2022-04-29T02:02:12+03:00

kolezko [41]2 years ago

3 0

Answer:

m = 0.5679 Kg

Explanation:

Given

v = 9 m/s

K = 23 KJ

m = ?

We apply the equation

K = 0.5*m*v² ⇒ m = 2*K/v²

⇒ m = 2*23000 J/(9 m/s)² = 567,9 Kg

A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m ​ 9, point, 0, start fraction, start text, m, end text, div

A brown bear runs at a speed of 9.0\,\dfrac{\text m}{\text s}9.0 s m 9, point, 0, start fraction, start text, m, end text, div