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Marina86 [1]
3 years ago
13

A 2 kg object is released from rest from a height of 3 m above Earth's surface. How much kinetic energy does the object have whe

n it reaches a height of 1 m? (A) 2.5 J (B) 10 J (C) 20 J (D) 30 J (E) 40 JFigure:A 2kg object is hanging
Physics
1 answer:
borishaifa [10]3 years ago
4 0

Answer:

Kinetic energy, E = 40 Joules

Explanation:

Given that,

Mass of the object, m = 2 kg

It is released from rest from a height of 3 m above Earth's surface, h_1=3\ m

We need to find the kinetic energy the object have when it reaches a height of 1 m, h_2=1\ m

It is a case of conservation of mechanical energy. It states that the total energy of the system remains constant. The kinetic energy is given by :

E=mg(h_1-h_2)

E=2\times 10\times (3-1)

E = 40 Joules

So, the kinetic energy of the object when it reaches a height of 1 m is 40 joules. Hence, this is the required solution.

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a 1500kg weather rocket is launched upward from the ground and accelerates at 10m/s it explodes 4s after lifeoff and breaks into
saveliy_v [14]

Answer:

v_h = 9 m/s

Explanation:

given,

mass of the rocket = 1500 kg

accelerates = 10 m/s²

time = 4 s

one fragment is twice as massive as the other.

maximum height reached by the lighter fragment = 530 m

now,

using equation of motion to calculate the velocity

initial velocity of rocket,u = 0 m/s

v = u + a t

v = at.......(1)

total mass of the rocket

M = m + m'

m' is the heavier particle mass.

m' = 2 m (from the statement given in the question)

M = 3 m

m = M/3

now, again using equation  of motion to calculate the initial velocity of the lighter particle.

v² = u² + 2 a s

0² = u² + 2 g h

u = √2gh.....(2)

now,

using conservation of momentum,

M v = m u + m' v_h

M at = \dfrac{M}{3}u + \dfrac{2M}{3}v_h

at = \dfrac{u}{3}+ \dfrac{2v_h}{3}

10\times 4 = \dfrac{\sqrt{2gh}}{3}+ \dfrac{2v_h}{3}

120= \sqrt{2\times 9.8 \times 530}+2v_h

   2 v_h = 18

        v_h = 9 m/s

speed of the heavy fragment is equal to 9 m/s

6 0
4 years ago
A ball is thrown vertically upward with a speed of 12.0 m/s. (<br> a. How high does it rise?
sdas [7]
It rises till all of its Kinetic energy is converted into potential energy.

so, mgh=(1/2)m(v^2)

so, h=(v^2)/2g = 12*12/(2*9.81)=7.34 m
5 0
3 years ago
What is the specific latent heat of fusion of water?
slava [35]

Answer:

334

Explanation:

7 0
3 years ago
A 1.1-cm-diameter pipe widens to 2.34 cm, then narrows to 4.9 mm. Liquid flows through the first segment at a speed of 3.57 m/s.
ratelena [41]

Answer:

v2=0.79 m/s

Explanation:

equation of continuity: V1A1=V2A2

A=(pi)r^2

A1=(pi)(0.55cm)^2

A2=(pi)(1.17cm)^2

convert cm2->m2

A1= 0.95cm2=

A2= 4.3cm2=

(3.57 m/s)(0.000095 m^2)=(x m/s)(0.00043 m^2)

v2=0.79 m/s

hope this helped

6 0
3 years ago
A passenger at the rear of a train traveling at 15 m/s relative to earth throws a baseball with a speed of 15 m/s in the directi
matrenka [14]
Relative to the earth, the trains' speed is 15 m/s.
Relative to the train, the ball's speed is -15 m/s.

Therefore, relative to earth, the ball's speed is
15 - 15 = 0

Answer: 0
6 0
3 years ago
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