Answer:
v_h = 9 m/s
Explanation:
given,
mass of the rocket = 1500 kg
accelerates = 10 m/s²
time = 4 s
one fragment is twice as massive as the other.
maximum height reached by the lighter fragment = 530 m
now,
using equation of motion to calculate the velocity
initial velocity of rocket,u = 0 m/s
v = u + a t
v = at.......(1)
total mass of the rocket
M = m + m'
m' is the heavier particle mass.
m' = 2 m (from the statement given in the question)
M = 3 m
m = M/3
now, again using equation of motion to calculate the initial velocity of the lighter particle.
v² = u² + 2 a s
0² = u² + 2 g h
u = √2gh.....(2)
now,
using conservation of momentum,





2 v_h = 18
v_h = 9 m/s
speed of the heavy fragment is equal to 9 m/s
It rises till all of its Kinetic energy is converted into potential energy.
so, mgh=(1/2)m(v^2)
so, h=(v^2)/2g = 12*12/(2*9.81)=7.34 m
Answer:
v2=0.79 m/s
Explanation:
equation of continuity: V1A1=V2A2
A=(pi)r^2
A1=(pi)(0.55cm)^2
A2=(pi)(1.17cm)^2
convert cm2->m2
A1= 0.95cm2=
A2= 4.3cm2=
(3.57 m/s)(0.000095 m^2)=(x m/s)(0.00043 m^2)
v2=0.79 m/s
hope this helped
Relative to the earth, the trains' speed is 15 m/s.
Relative to the train, the ball's speed is -15 m/s.
Therefore, relative to earth, the ball's speed is
15 - 15 = 0
Answer: 0