Answer:
a
b
Explanation:
Generally the force of attraction between this two irons is mathematically represented as
![F = \frac{k * [Q_{Li} ] * [Q_{O} ] }{ r^2}](https://tex.z-dn.net/?f=F%20%3D%20%20%5Cfrac%7Bk%20%2A%20%20%5BQ_%7BLi%7D%20%20%5D%20%2A%20%5BQ_%7BO%7D%20%20%5D%20%20%7D%7B%20r%5E2%7D)
Here k is known as the proportionality constant with value 
substituting -2 for 
i.e the charge on oxygen , +1 for 
i.e the charge on Lithium and ![[0.140 + 0.068 ] nm= 0.208 nm = 0.208*10^{-9}](https://tex.z-dn.net/?f=%20%5B0.140%20%2B%200.068%20%5D%20nm%3D%200.208%20nm%20%3D%20%200.208%2A10%5E%7B-9%7D%20%20%20)
for r
So
Generally the force of repulsion will be the magnitude but different direction to the force o attraction
So Force of repulsionn is
Answer:
Im pretty sure 1 is gravity, 2 is force
Explanation:
The Ozone layer is responsible for the absorption of harmful
radiation from the sun before it hits the surface or exterior structure of our
planet. It is known to be a belt of a known occurring gas, known as “ozone”
which is sealed around the Earth’s atmosphere. It serves as a shield, which absorbs
most of the sun’s ultraviolet radiation.
Actually what the problem meant about the westward
component of the ball’s displacement is the horizontal component of the
displacement. To help us better understand the problem, I attached a figure of
the situation.
We can see from the figure that to solve for the value of
the horizontal component, we have to make use of the sin function. That is:
sin θ = side opposite to the angle / hypotenuse of the
triangle
sin 42 = x / 40 m
x = (40 m) sin 42
x = 26.77 m
Therefore the ball has a westward
displacement of about 26.77 m
Answer:
a. The moment of the 4 N force is 16 N·m clockwise
b. The moment of the 6 N force is 12 N·m anticlockwise
Explanation:
In the figure, we have;
The distance from the point 'O', to the 6 N force = 2 m
The position of the 6 N force relative to the point 'O' = To the left of 'O'
The distance from the point 'O', to the 4 N force = 4 m
The position of the 4 N force relative to the point 'O' = To the right of 'O'
a. The moment of a force about a point, M = The force, F × The perpendicular distance of the force from the point
a. The moment of the 4 N force = 4 N × 4 m = 16 N·m clockwise
b. The moment of the 6 N force = 6 N × 2 m = 12 N·m anticlockwise.
