One thing you should notice. It is kind of weird. Ke has no direction so that fact that it has velocities associated with it does not matter. It becomes a scaler (something measured by amount alone).
General Formula
Ke = 1/2 m v^2
Formula for this problem
Ke = 1/2 m (v2)^2 - 1/2 m (v1)^2
Givens
m = 1200 kg
v2 = 100 km/hr = 100 km/h * [1 hour / 3600 sec] * [1000 m/ 1km] = 27.8 m/s
v1 = 50 km / hr = 13.9 m/s
Substitution and work.
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delta Ke = 1/2 1200 (27.8)^2 - 1/2 1200 (13.9)^2
delta Ke = 463704 - 115926
delta Ke = 34778 Joules
delta Ke = 34.8 kJ
The change is 34.8 kJ which means that the vehicle gains 34.8 kJ
The third one because it is a small one and it had high and high temp so it has the most modecules.
Hope this helps
Answer:
B. to the right
Explanation:
Given:
- distance of the test charge from +Q, r
- distance of test charge from +2Q, 2r
<u>Force on the test charge due to +Q:</u>
<u>Force on the test charge due to +Q:</u>
Since all the charges are positive here, so they will try to repel the test charge away. And the force due to charge +Q will be greater so initially the test charge will move rightwards away from the +Q charge.
Answer:
Linear velocity of the club head is 40 m/s
Explanation:
To calculate the linear velocity of the club head, we just need to multiply the angular velocity of the driver (Av = 20 rad/s) by the distance from the club head to the axis of rotation (d = 2.0 m)
So, the linear velocity of the club head (Lv) is:
Lv = Av * d = 20 * 2 = 40 m/s
I am going to assume 2.1 metres per second and that we're rounding acceleration due to gravity to -10 metres per second squared. At the highest point, velocity is going to be 0. v= intial velocity + acceleration*time, sub in 0 for velocity, 2.1 for initial velocity and -10 for acceleration to get 0= 2.1-10t. Now solve for t. t=0.21 seconds.
