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dolphi86 [110]
2 years ago
12

you toss a bowling ball straight up into the air with a speed of 2.1. how long does it take the bowling ball to reach its highes

t point?
Physics
2 answers:
VMariaS [17]2 years ago
8 0

Answer:

0.2 s

Explanation:

Apex; good luck all! :)

omeli [17]2 years ago
3 0
I am going to assume 2.1 metres per second and that we're rounding acceleration due to gravity to -10 metres per second squared. At the highest point, velocity is going to be 0. v= intial velocity + acceleration*time, sub in 0 for velocity, 2.1 for initial velocity and -10 for acceleration to get 0= 2.1-10t. Now solve for t. t=0.21 seconds.
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Definition of measurements?​
skad [1K]

Answer:

Measurement is a comparison of an unknown quantity with a known fixed quantity of the same kind. The value obtained on measuring a quantity is called its magnitude. The magnitude of a quantity is expressed as numbers in its unit.

8 0
3 years ago
rectangular plate, whose streamwise dimension (or chord c) is 0.2 m and whose width (or span b) is 1.8 m, is mounted in a wind t
Andrei [34K]

Answer:

See explaination for the details of the answer.

Explanation:

Density is a measurement that compares the amount of matter an object has to its volume. An object with much matter in a certain volume has high density An object with little matter in the same amount of volume has a low density. Density is found by dividing the mass of an object by its volume.

The Calculate of the chordwise distribution of the skin friction coefficient and the displacement thickness is done and represented in the attachment.

Please kindly check attachment for the step by step answer.

8 0
3 years ago
Titanium metal requires a photon with a minimum energy of 6.94×10−19J to emit electrons. If titanium is irradiated with light of
butalik [34]

Answer:

a) 1.59(10)^{-19} J

b) 2.34(10)^{12} electrons

Explanation:

The photoelectric effect consists of the emission of electrons (electric current) that occurs when light falls on a metal surface under certain conditions.  

If the light is a stream of photons and each of them has energy, this energy is able to pull an electron out of the crystalline lattice of the metal and communicate, in addition, a kinetic energy.  

<u>This is what Einstein proposed: </u>

Light behaves like a stream of particles called photons with an energy  E:

E=\frac{hc}{\lambda} (1)  

So, the energy E of the incident photon must be equal to the sum of the Work function \Phi of the metal and the kinetic energy K of the photoelectron:  

E=\Phi+K (2)  

Where \Phi=6.94(10)^{-19} J is the minimum amount of energy required to induce the photoemission of electrons from the surface of Titanium metal.

Knowing this, let's begin with the answers:

<h3 /><h3>a)  Maximum possible kinetic energy of the emitted electrons (K)</h3>

From (1) we can know the energy of one photon of 233 nm light:

E=\frac{hc}{\lambda}

Where:

h=6.63(10)^{-34}J.s is the Planck constant  

\lambda=233 (10)^{-9} m is the wavelength

c=3 (10)^{8} m/s is the speed of light

E=\frac{(6.63(10)^{-34}J.s)(3 (10)^{8} m/s)}{3 (10)^{8} m/s} (3)

E=8.53(10)^{-19} J (4) This is the energy of one 233 nm photon

Substituting (4) in (2):

8.53(10)^{-19} J=6.94(10)^{-19} J+K (5)  

Finding K:

K=1.59(10)^{-19} J (5)  This is the maximum possible kinetic energy of the emitted electrons

<h3>b) Maximum number of electrons that can be freed by a burst of light whose total energy is 2 \mu J=2(10)^{-6} J</h3>

Since one photon of 233 nm is able to free at most one electron from the Titanium metal, we can calculate the following relation:

\frac{E_{burst}}{E}

Where E_{burst}=2(10)^{-6} J is the energy of the burst of light

Hence:

\frac{E_{burst}}{E}=\frac{2(10)^{-6} J}{8.53(10)^{-19} J}=2.34(10)^{12} electrons This is the maximum number of electrons that can be freed by the burst of light.

4 0
3 years ago
The rate constant of a chemical reaction increased from 0.100 s−1 to 3.10 s−1 upon raising the temperature from 25.0 ∘C to 51.0
forsale [732]

Answer:

A. (1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹

B. ln (k₁/k₂) = -3.434

C. E = 106.13 KJ/mol

Explanation:

Part A:

we have:

T₁ = 25°C = 298 K

T₂ = 51°C = 324 K

(1/T₂ - 1/T₁) = (1/324 k - 1/298 k)

<u>(1/T₂ - 1/T₁) = -2.69 x 10⁻⁴ K⁻¹</u>

<u></u>

Part B:

ln (k₁/k₂) = ln (0.1/3.1)

<u>ln (k₁/k₂) = -3.434</u>

Part C:

The activation energy can be found out by using Arrhenius Equation:

ln (k₁/k₂) = E/R  (1/T₂ - 1/T₁)

where,

E = Activation Energy

R = General Gas Constant = 8.314 J/mol.k

Therefore,

-3.434 = (E/8.314 J/mol.k)(-2.69 x 10⁻⁴ K⁻¹)

<u>E = 106134.8 J/mol = 106.13 KJ/mol</u>

8 0
3 years ago
Is there a relationship between the direction of movement and distribution of earthquakes? volcanoes? both? neither?
iogann1982 [59]

Yes. With converging plates, where two plates are touching towards each other instigating one to sub duct beneath the other, you incline to have volcanoes and earthquakes. Instance: In Asia, the Pacific Plate touching to and beneath the Eurasian Plate. Another example of where you would have earthquakes is where two plates are slipping in contrary directions parallel to one another. This is an instance of the Pacific Plate touching next to the North American Plate. This makes faults or crashes in the plates instigating earthquakes. As the plate slip past each other, subsequently separately plate boundary isn't flawlessly smooth, they catch on one another and accumulate pressure. When the pressure is free, the energy is gave out as an earthquake.

3 0
3 years ago
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