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DedPeter [7]
3 years ago
12

Can someone help me please, ASAP!! Thank you!

Mathematics
1 answer:
forsale [732]3 years ago
4 0
Use a proportional that will give you x=4
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PLS HURRY WILL GIVE BRAINLIEST
marta [7]

Answer:

C. y= 6x-5

Step-by-step explanation:

Given Information :

Slope (m) = 6

y-intercept (b) = -5

Equation of a line :

y=mx+b

Where :

m = slope

b = y-intercept

So , with the given the information , the equation is :

y = 6x - 5

7 0
3 years ago
Jill earn $15 per hour babysitting class a transportation fee of five dollars per job. Write a formula for E, Ji Jill earn $15 p
daser333 [38]
Since you know the amount of what she earns you would use the number 15 and you dont know how long she worked you would put "x" next to the 15. so you would have 15x and then put a plus 5 to show her transportation fee. so you would have the equation of 15x+5:) and instead of x use h to show hours because h=hours

you feel me?
great!
6 0
3 years ago
Compute 7-9-2+10-4?
alexandr1967 [171]
I believe it would be 2. Since 7-9= -2 then subtract another 2 which equals -4 then add 10 which equals 6 then subtract 4. Which equals 2.

2 is the answer, hope this helps

3 0
3 years ago
Question 2(Multiple Choice Worth 4 points) (08.02)A pair of equations is shown below. x + y = 5 y = one halfx + 2 If the two equ
8_murik_8 [283]

Answer:

(2,3)

Step-by-step explanation:

The first equation is  x+y=5

The second equation is y=\frac{1}{2}x+2

When we graph these two equations, <em>they will meet at a point which represent the solution of the two equations</em>.

We can solve the two equations simultaneously to determine their point of intersection.

Let us substitute the second equation into the first equation to get;

x+\frac{1}{2}x+2=5

Multiply through by 2 to get;

2x+x+4=10

Group similar terms to obtain;

2x+x=10-4

Simplify;

3x=6

Divide both sides by 3;

\Rightarrow x=2

Put x=2 into the second equation;

y=\frac{1}{2}(2)+2

\Rightarrow y=1+2

\Rightarrow y=3

Therefore the graphs of the two functions intersect at (2,3)

See graph in attachment.

3 0
3 years ago
Help me and am I doing this right
Nat2105 [25]
Looks write but i think ur missing somthing
5 0
3 years ago
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