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sukhopar [10]
2 years ago
6

The extent of crystal field splitting is often determined from spectra.(a) Given the wavelength (λ) of maximum absorption, find

the crystal field splitting energy (Δ), in kJ/mol, for each of the following complex ions:
Chemistry
1 answer:
kenny6666 [7]2 years ago
7 0

Crystal field splitting is the difference in energy between d orbitals of ligands. Crystal field splitting number is denoted by the capital Greek letter Δ. Crystal field splitting explains the difference in color between two similar metal-ligand complexes.

<h3>What is crystal field splitting of d-orbitals?</h3>

The splitting of fivefold degenerate d orbitals of the metal ion into two levels in a tetrahedral crystal field is the representation of two sets of orbitals as Td. The electrons in dx2-y2 and dz2 orbitals are less repelled by the ligands than the electrons present in dxy, dyz, and dxz orbitals.

<h3>Which of the following factors affect crystal field splitting energy?</h3>

There are the following factors that affect the crystal field splitting. These are the nature of ligands, coordination number, arrangement of ligand, size of a metal atom, charge on the metal atom, size of ligands, electronegativity, and interatomic distance.

Learn more about crystal field splitting here:

<h3>brainly.com/question/13004475</h3>

<h3>#SPJ4</h3>
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k0ka [10]

Answer:

A chemical equation is balanced when the number of each kind of atom is the same on both sides of the reaction.

Explanation:

    The law of conservation of matter (except in nuclear reactions) indicates that atoms can neither be created or destroyed.

    The number of atoms that are in the  reactants must be the same as the number of the atoms that are in the product.

    The number and types of molecules can (and will) change. The atoms that make up the molecules are rearranged but the number and kinds of atoms stay the same.  

3 0
3 years ago
For the gas phase decomposition of 1-bromopropane, CH3CH2CH2BrCH3CH=CH2 + HBr the rate constant at 622 K is 6.43×10-4 /s and the
ladessa [460]

<span>Answer is: activation energy of this reaction is 212,01975 kJ/mol.
Arrhenius equation: ln(k</span>₁/k₂) = Ea/R (1/T₂ - 1/T₁<span>).
k</span>₁<span> = 0,000643 1/s.
k</span>₂ = 0,00828 1/s.

T₁ = 622 K.

T₂ = 666 K.

R = 8,3145 J/Kmol.

1/T₁<span> = 1/622 K = 0,0016 1/K.
1/T</span>₂<span> = 1/666 K = 0,0015 1/K.
ln(0,000643/0,00828) = Ea/8,3145 J/Kmol · (-0,0001 1/K).
-2,55 = Ea/8,3145 J/Kmol · (-0,0001 1/K).
Ea = 212019,75 J/mol = 212,01975 kJ/mol.</span>

4 0
3 years ago
Someone help answer this
alexandr402 [8]

it is water energy :) this is easy

6 0
3 years ago
Read 2 more answers
What is the molarity of a solution made by dissolving 20.0 g of H3PO4 in 50.0 mL of solution
Rom4ik [11]
(20*1000)÷(molecular weight of H3po4*50)

8 0
3 years ago
A chemistry student needs 60.0 g of 2-ethyltoluene for an experiment. He has available 1.5 kg of a 15.3% w/w solution of 2 ethyl
Mila [183]

Answer:

392 g

Explanation:

The given concentration tells us that<em> in 100 g of solution, there would be 15.3 g of 2-ethyltoluene</em>.

With that in mind we can<u> calculate how many grams of solution would contain 60.0 g of 2-ethyltoluene</u>:

  • Mass of solution * 15.3 / 100 = 60.0 g 2-ethyltoluene
  • Mass of solution = 392 g
8 0
3 years ago
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