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Alika [10]
3 years ago
14

PLEASE HELP ME Which of the following is a Brønsted-Lowry base but not an Arrhenius base?

Chemistry
1 answer:
never [62]3 years ago
4 0
Ur answer is going to be <span>NH 3 or D AND PLEASE MARK ME AS BRAINLIEST CAUSE IVE NEVER GOT BRAINLIEST BEFORE AND HAVE A GOOD DAY !</span>
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El desplazamiento de la Tierra alrededor del Sol se conoce como
Lapatulllka [165]
Le déplacement est défini comme la distance entre la position initiale et finale du corps. Après un tour complet, la terre revient à sa position initiale. La distance entre la position initiale et la position finale est donc nulle.
Le déplacement de la terre est donc nul. Par conséquent, la déclaration donnée est vraie.
3 0
3 years ago
Read 2 more answers
Write the empirical formula for at least four ionic compounds that could be formed from the following ions:
love history [14]

Answer:

FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

Explanation:

Empirical formula of ionic compound formed by two ions A^{x+} and B^{y-} is A_{y}B_{x} (for x\neq y) of AB (for x = y)

The above empirical formula is in accordance with charge neutrality principle

Here each cation (Fe^{3+} and Fe^{2+}) can form two ionic compounds by combining with two given anions (SO_{4}^{2-} and CH_{3}CO^{2-}).

So the four ionic compounds are: FeSO_{4},FeCH_{3}CO,Fe_{2}(SO_{4})_{3},Fe_{2}(CH_{3}CO)_{3}

4 0
4 years ago
I need the Formulas for:
andrey2020 [161]

Explanation:

mass = desity × volume

volume = mass/density...

i believe thats right...

btw u means Physics formulae only..lol

3 0
4 years ago
7. If one container holds 3.45 gallons of gas, how many containers would I need to hold 17
NNADVOKAT [17]

Answer:

5

Explanation:

if you do 17/3.45

=4.9 but if you round it up to the nearest whole number 5.

3.45*5=17.25

it equals to 17.25

7 0
3 years ago
The molar concentration (M) of a solution prepared by dissolving 0.2362g of Cr(NO3)3 in a 50-mL volumetric flask is 0.01985M, wh
kati45 [8]

Answer:

Use a 10 mL pipet and a 50 mL volumetric flask, <em>twice</em>

Explanation:

Given those conditions, in order to have a solution that is 25 times less concentrated that the one previously prepared, we would need two dillution steps, as suggested by the problem.

If we take an aliquot of 10 mL and dilute it to a final volume of 50 mL, we prepare a solution that is 5 times less concentrated. And if we then take again an aliquot of 10 mL of that dilluted solution and dilute it to a final volume of 50 mL, we would have a solution 25 (5 times 5) times less concentrated than the original one.

In order to verify, we can calculate the resulting concentration and compare it with the original one:

0.01985M*\frac{10mL}{50mL} *\frac{10mL}{50mL}=0.000794M

Thus we can see that the obtained concentration is in fact 25 times lower than the original concentration.

3 0
3 years ago
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