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Alika [10]
3 years ago
14

PLEASE HELP ME Which of the following is a Brønsted-Lowry base but not an Arrhenius base?

Chemistry
1 answer:
never [62]3 years ago
4 0
Ur answer is going to be <span>NH 3 or D AND PLEASE MARK ME AS BRAINLIEST CAUSE IVE NEVER GOT BRAINLIEST BEFORE AND HAVE A GOOD DAY !</span>
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What is the correct equilibrium constant expression for equation P2(g)
sertanlavr [38]

Answer:

k = [F2]² [PO]² / [P2] [F2O]²

Explanation:

In a chemical equilibrium, the equilibrium constant expression is written as the ratio between the molar concentration of the products over the molar concentration of the reactants. Each species powered to its reaction coefficient. For the equilibrium:

P2(g) + 2F2O(g) ⇄ 2PO(g) + 2F2(g)

The equilibrium constant, k, is:

k = [F2]² [PO]² / [P2] [F2O]²

6 0
3 years ago
To insert a thermometer into an adapter, use choose. To prepare the thermometer. Then, hold the thermometer choose. The adapter
vova2212 [387]

To insert a thermometer into an adapter, use <u>mineral oil</u> to prepare the thermometer. Then, hold the thermometer <u>close to</u> the adapter and<u> slowly turn</u> the thermometer into the adapter.

The term "temperature" refers to a measurement of how cold or hot an actual physical object is. It is measured with a thermometer, which gives readings in Celsius, Kelvin, and Fahrenheit (°C, K, and °F).

The average kinetic energy of the particles in a given substance is often measured by temperature. A thermometer is a tool used to gauge a substance's or a body's temperature (degree of hotness or coolness). It is a bulb-shaped piece of thin glass that usually contains either coloured alcohol or mercury.

In order to get readings throughout the distillation process, a thermometer adapter is used with a temperature probe. Use mineral oil to prepare or make the thermometer suitable before inserting it into the adapter. After that, slowly insert the thermometer into the adaptor while holding it close to it.

Learn more about thermometer:

brainly.com/question/2339046

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7 0
1 year ago
We want to calculate the concentrations of all species in a 0.58 M Na 2 SO 3 (sodium sulfite) solution. The ionization constants
NeX [460]

Explanation:

Reaction equation is as follows.

      Na_{2}SO_{3}(s) \rightarrow 2Na^{+}(aq) + SO^{2-}_{3}(aq)

Here, 1 mole of Na_{2}SO_{3} produces 2 moles of cations.

[Na^{+}] = 2[Na_{2}SO_{3}] = 2 \times 0.58

                                  = 1.16 M

[SO^{2-}_{3}] = [Na_{2}SO_{3}] = 0.58 M

The sulphite anion will act as a base and react with H_{2}O to form HSO^{-}_{3} and OH^{-}.

As,     K_{b} = \frac{K_{w}}{K_{a_{2}}}

                       = \frac{10^{-14}}{6.3 \times 10^{-8}}

                       = 1.59 \times 10^{-7}

According to the ICE table for the given reaction,

          SO^{2-}_{3} + H_{2}O \rightleftharpoons HSO^{-}_{3} + OH^{-}

Initial:        0.58             0              0

Change:     -x               +x             +x

Equilibrium: 0.58 - x     x               x

So,

        K_{b} = \frac{[HSO^{-}_{3}][OH^{-}]}{[SO^{2-}_{3}]}

 1.59 \times 10^{-7} = \frac{x^{2}}{0.58 - x}

        x^{2} = 1.59 \times 10^{-7} \times (0.58 - x)

                x = 0.0003 M

So,   x = [HSO^{-}_{3}] = [OH^{-}] = 0.0003 M

[SO^{2-}_{3}] = 0.58 - 0.0003

                     = 0.579 M

Now, we will use [HSO^{-}_{3}] = 0.0003 M

The reaction will be as follows.

              HSO^{2-}_{3} + H_{2}O \rightleftharpoons H_{2}SO_{3} + OH^{-}

Initial:   0.0003

Equilibrium:  0.0003 - x        x             x

              K_{b} = \frac{x^{2}}{0.0003 - x}

        K_{b} = \frac{K_{w}}{K_{a_{1}}}

                      = \frac{10^{-14}}{1.4 \times 10^{-2}}

                      = 7.14 \times 10^{-13}

Therefore,  7.14 \times 10^{-13} = \frac{x^{2}}{0.0003 - x}

As,  x <<<< 0.0003. So, we can neglect x.

Therefore,  x^{2} = 7.14 \times 10^{-13} \times 0.0003

                              = 0.00214 \times 10^{-13}

                     x = 0.0146 \times 10^{-6}

x = [OH^{-}] = [H_{2}SO_{3}] = 1.46 \times 10^{-8}

    [H^{+}] = \frac{10^{-14}}{[OH^{-}]}

                = \frac{10^{-14}}{0.0003}

                = 3.33 \times 10^{-11} M

Thus, we can conclude that the concentration of spectator ion is 3.33 \times 10^{-11} M.

5 0
3 years ago
Is it true that an atom has 3 subatomic particles with a negative nucleus and the neutrons outside the the nucleus
Nostrana [21]

Answer: atoms do have 3 subatomic particles but the nucleus is positive and the nucleus consists of protons and neutrons. Its positive because neutrons have no charge and protons have a positive charge. There are only electrons on the shells so no neutrons or protons on the shells

Explanation:

5 0
3 years ago
Explain how impurities are selected for doping in group 14 semiconductors
aleksklad [387]

Impurities selection for doping in group 14 semiconductors is: based on their ability to add more holes and fewer electrons or to add more electrons and reduce the holes.

<h3>Meaning of Semiconductors</h3>

Semiconductors can be defined as any material that has the ability to exhibit some properties of a conductor and some properties of an insulator.

A semiconductor can be used as either a conductor or an insulator when worked upon.

In conclusion, Impurities selection for doping in group 14 semiconductors is: based on their ability to add more holes and fewer electrons or to add more electrons and reduce the holes.

Learn more about semiconductors: brainly.com/question/1918629

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6 0
2 years ago
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