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riadik2000 [5.3K]
3 years ago
13

In Universe L , recently discovered by an intrepid team of chemists who also happen to have studied interdimensional travel, qua

ntum mechanics works just as it does in our universe, except that there are four d orbitals instead of the usual number we observe here. Use these facts to write the ground-state electron configurations of the third and fourth elements in the first transition series in Universe L .
Chemistry
1 answer:
ch4aika [34]3 years ago
3 0

Answer:

See explanation

Explanation:

The third element in the first transition series is Vanadium

The fourth element in the first transition series is chromium

Given that we have four d orbitals in universe L instead of five as we have on earth;

The electronic configuration of Vanadium in universe L is;

Ar 3d3 4s2

The electronic configuration of chromium in universe L is;

[Ar] 3d4 4s2

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The three major types of faults are Normal, Reverse and Strike-slip faults. 


Answer: FALSE
6 0
3 years ago
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Sulfuric acid dissolves aluminum metal according to the following reaction:
Fiesta28 [93]

Answer:

m_{H_2SO_4}=81.7gH_2SO_4

m_{H_2}=1.67gH_2

Explanation:

Hello,

Based on the given undergoing chemical reaction is is rewritten below:

2Al (s) + 3H_2SO_4 (aq)\rightarrow  Al _2(SO4)_3 (aq) + 3H_2 (g)

By stoichiometry we find the minimum mass of H2SO4 (in g) as shown below:

m_{H_2SO_4}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2SO_4}{2molAl}*\frac{98gH_2SO_4}{1molH_2SO_4} \\m_{H_2SO_4}=81.7gH_2SO_4

Moreover, mass of H2 gas (in g) would be produced by the complete reaction of the aluminum block turns out:

m_{H_2}=15.0gAl*\frac{1molAl}{27gAl}*\frac{3molH_2}{2molAl}*\frac{2gH_2}{1molH_2} \\m_{H_2}=1.67gH_2

Best regards.

3 0
3 years ago
6. Calculate the molarity if 35.0 grams of KBr are dissolved in 700. ml?
olga55 [171]

Answer:

To calculate molarity, divide the number of moles of solute by the volume of the solution in liters. If you don't know the number of moles of solute but you know the mass, start by finding the molar mass of the solute, which is equal to all of the molar masses of each element in the solution added together.

Explanation:

try starting with 35.0 and dived it by the volume

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(Science)<br> why is the 10g of shampoo is more dense than the 10kg of the same shampoo?
igor_vitrenko [27]
Grams (g) is much lighter than kilograms (kg)
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3 years ago
1. If 22.5 L of nitrogen at 734 mm Hg are compressed to 702 mm Hg at constant
Alika [10]

Answer:

The answer to your question is   V2 = 23.52 l

Explanation:

Data

Volume 1 = V1 = 22.5 l

Pressure 1 = P1 = 734 mmHg

Volume 2 = V2 = ?

Pressure 2 = 702 mmHg

Process

To solve this problem use Boyle's law.

                      P1V1 = P2V2

-Solve for V2

                          V2 = P1V1 / P2

-Substitution

                          V2 = (734 x 22.5) / 702

-Simplification

                           V2 = 16515 / 702

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                           V2 = 23.52 l

-Conclusion

If we diminish the pressure, the volume will be higher.

8 0
3 years ago
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