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Ymorist [56]
3 years ago
12

The human body can get energy by metabolizing proteins, carbohydrates or fatty acids, depending on the circumstances. Roughly sp

eaking, the energy it gets comes mostly from allowing all the carbon atoms in the food molecules to become oxidized to carbon dioxide CO2 by reaction with oxygen from the atmosphere. Hence the energy content of food is roughly proportional to the carbon content.
Let's consider alanine, C3H7NO2, one of the amino acids from which proteins are made, and glucose C6H12O6, one of the simplest carbohydrates. Using the idea above about energy content, calculate the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose.
Chemistry
1 answer:
Kamila [148]3 years ago
7 0

Answer:

the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

Explanation:

Given the data in the question;

To determine the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose, first we get the molar masses of both alanine and glucose

we know that;

Molar mass of alanine ( C₃H₇NO₂ ) = 89.09 g/mol

Molar mass of glucose ( C₆H₁₂O₆ ) = 180.16 g/mol

now, { metabolizing each gram }

moles of alanine = mass taken / molar mass

= 1g / 89.09 g/mol = 1/89.09 moles

moles of glucose = mass taken / molar mass

= 1g / 180.16 g/mol = 1/180.16 moles

In each molecule of alanine, we have 3 atoms  of carbon.

Also, in each molecules of glucose, we have 6 atoms of carbon

so,

number of moles of Carbons in alanine = 3 × 1/89.09 moles = 0.03367

number of moles of Carbons in glucose = 6 × 1/180.16 moles = 0.0333

so ratio of energy will be the ratio of carbon atoms, which is;

⇒ 0.03367 / 0.0333 = 1.0111

Therefore, the ratio of the energy the body gets metabolizing each gram of alanine to the energy the body gets metabolizing each gram of glucose is 1.0111

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Volume of 14.00g of nitrogen at 5.64atm and 315k
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The volume of a 14.00g of nitrogen at 5.64atm and 315K is 4.59L.

<h3>How to calculate volume?</h3>

The volume of an ideal gas can be calculated using the following ideal gas equation formula;

PV = nRT

Where;

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The number of moles in 14g of nitrogen can be calculated as follows:

moles = 14g ÷ 14g/mol = 1mol

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1 year ago
At 393 K, the pressure of a sample of nitrogen is 1.07 atm. What will the pressure be at 478 K, assuming constant volume?
True [87]

Answer:

About 1.301 atm

Explanation:

The formula that you should is PV=nRT, where P stands for pressure, V stands for volume, n stands for the number of moles, R stands for the universal gas constant, and T stands for temperature in Kelvin. Since the volume, number of moles, and universal gas constant don't change, you don't need to worry about them.

1.07V=393nR

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P=1.301 atm. Hope this helps!

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