Answer:
Boiling Point!
Explanation:
Hope this helps. Good luck!
Answer:
3.8 M
Explanation:
Volume of acid used VA= 57.0 - 37.5 = 19.5 ml
Volume of base used VB= 67.8 - 45.0 = 22.8 ml
Equation of the reaction
2HNO3(aq) + Ca(OH)2(aq) --------> Ca(NO3)2(aq) + 2H2O(l)
Number of moles of acid NA= 2
Number of moles of base NB= 1
Concentration of acid CA= ???
Concentration of base CB= 1.63 M
CAVA/CBVB = NA/NB
CAVANB = CBVBNA
CA= CBVBNA/VANB
CA= 1.63 × 22.8 × 2/ 19.5 × 1
CA= 3.8 M
HENCE THE MOLARITY OF THE ACID IS 3.8 M.
Its no doubt
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The answer is prokaryote :)
Answer:
V=0.430 Liters
Explanation:
First off you need to convert ml to l and celsius to kelvin, in order for them to be in the S.I.
So, 350.0mL is 0.350 L and 23.0 C is (273.15+23=) 296.15 K (you can ignore the 0.15)
From the equation pV=nRT, lets name this equation (1), we can tell that the number of moles, pressure, and R, stay the same. The only thing changing is the volume, and temperature.
With the information given, let's figure out the pressure. From equation (1) if we solve it for the pressure of the gas, p=nRT/V => p=nR*296.15/0.350 => p=846.15 *nR
Now, we have to figure out the volume of the gas at 90.0 C (363.15 K), and solve equation (1) for volume, using the pressure we previously found.
v=nRT/p => v=nR*363.15/846.15*nR => (the nR's from top and bottom go away) v=0.429 L
Since we used 273.15 for the conversion of celsius to Kelvin, we could round up the number to
V=0.430 Liters