5.38
21 divided by 3.9 is 5.38 and the equation for acceleration is change in velocity divided by time
Use Coulomb law: F = k * q1*q2 / (r^2), where k = 9.00 * 10^9 N.m^2/C^2
F = 9.00 * 10^9 N.m^2/C^2 * 2.4*10^-8 C * 1.8*10^-6 C / [0.008m]^2 = 38.88 * 10^ -5 N
F = 39 * 10 -5N
(a)
is the wavelength in air of such a sound wave.
(b)
is the wavelength of this wave in tissue.
<u>Explanation:</u>
Frequency and wavelength can be related by the equation,
Velocity = Wavelength x Frequency

where,
v - velocity of light for all EM (electromagnetic) waves in vacuum
Given:
f - 4.50 MHz = 
a) To find the wavelength in air
We know,
Speed of sound in air = 343 m/s
Apply given frequency and speed of sound in air, we get

b) If the speed of sound in tissue is 1500 m/s, find the wavelength of this wave in tissue
Speed of sound in tissue, v = 1500 m/s
