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Yuliya22 [10]
3 years ago
13

Do you think it is appropriate to have diet pop available in your school?

Chemistry
1 answer:
pashok25 [27]3 years ago
3 0

Answer:

I think so

Explanation:

It would provide an extra energy boost with lower sugars. Students bring drinks to school anyways so it would be nice to offer some that aren't as detrimental.

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Using the correct answer from Part B, calculate the volume of a rectangular prism with a length of 5.6 cm, a width of 2.1 cm, an
Alenkinab [10]
5.6 x 2.1 x 6.6 = 77.616 cm3
5 0
3 years ago
Consider the following: If the Earth's Crust are constantly moving, what
Vesnalui [34]

Answer:

the shape of the continents will continue to change, without even accounting for rising sea levels

Explanation:

5 0
3 years ago
What is a Spontaneous charge
ddd [48]

This means a release of free energy from the system corresponds to a negative change in free energy, but to a positive change for the surroundings.

3 0
3 years ago
An unknown liquid has a mass of 30.8 g, and a volume of 31.5 mL. What is the density of this liquid?
julsineya [31]

The density of the liquid is 0.98 g/mL

<h3>What is density? </h3>

The density of a substance is defined as the mass of the subtance per unit volume of the substance. Mathematically, it can be expressed as:

Density = mass / volume

With the above formula, we can obtain the density of the liquid.

<h3>How to determine the density </h3>
  • Mass = 30.8 g
  • Volume = 31.5 mL
  • Density =?

Density = mass / volume

Density of liquid = 30.8 / 31.5

Density of liquid = 0.98 g/mL

Learn more about density:

brainly.com/question/952755

3 0
2 years ago
How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
xenn [34]

Answer:

5.225x10^{22}atoms\ I

Explanation:

Hello!

In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):

n_{CaI_2}=12.75gCaI_2*\frac{1molCaI_2}{293.89gCaI_2}=0.0434molCaI_2

In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:

atoms\ I=0.0434molCaI_2*\frac{2molI}{1molCaI_2} *\frac{6.022x10^{23}atoms\ I}{1molI} \\\\atoms\ I = 5.225x10^{22}atoms\ I

Best regards!

4 0
3 years ago
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