How many atoms of iodine are in 12.75g of CaI2? Hint. How many Iodines are there in one CaI2 particle?
1 answer:
Answer:
Explanation:
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In this case, since 12.75 g of calcium iodide has the following number of moles (molar mass = 293.89 g/mol):
In such a way, since 1 mole of calcium iodide contains 2 moles of atoms of iodine, and one mole of atoms of iodine contains 6.022x10²³ atoms (Avogadro's number), we compute the resulting atoms as shown below:
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Answer : The entropy change for the surroundings of the reaction is, -198.3 J/K
Explanation :
We have to calculate the entropy change of reaction .
where,
= entropy of reaction = ?
n = number of moles
= standard entropy of
= standard entropy of
= standard entropy of
Now put all the given values in this expression, we get:
Therefore, the entropy change for the surroundings of the reaction is, -198.3 J/K