Question

a 68 ml aliquot of a 1.4M solution is diluted to a total volume of 288 ml a 144 ml portion of that solution is diluted by adding 173 ml of water what is the final concentration assume the volumes are dditive

Answer 1

Answer:

$0.1501\ \text{M}$

Explanation:

$68\times 10^{-3}\times 1.4=0.0952\ \text{mol}$

Concentration in solution

$\dfrac{95.2}{288}=0.3305\ \text{M}$

After dilution

$144\times 0.3305=47.592\ \text{mmol}$

Total volume $=144+173=317\ \text{mL}$

Final concentration $=\dfrac{47.592}{317}=0.1501\ \text{M}$

The final concentration is $0.1501\ \text{M}$