Answer:
d equal 10 this is the answer
Answer:
The minimum sample size we should anticipate using is 601.
Step-by-step explanation:
In a sample with a number n of people surveyed with a probability of a success of , and a confidence level of , we have the following confidence interval of proportions.
In which
z is the zscore that has a pvalue of .
The margin of error is:
We have no history with this characteristic, so we have no idea as to what the proportion might be.
This means that we use , which is when the largest sample size will be needed.
95% confidence level
So , z is the value of Z that has a pvalue of , so .
What is the minimum sample size we should anticipate using?
This is n for which M = 0.04. So
Rounding up, 601
The minimum sample size we should anticipate using is 601.
Step-by-step explanation:
just think it through :
0.4x + 20 < 200
0.4x < 180
x < 180/0.4 = 450
so, x < 450
they must order less than 450 bars.
therefore, the first answer option is correct :
they can order from 0 to 449 bars, but no more.
Answer:
x = 120°
Step-by-step explanation:
We are given;
sec²x + 4secx = -4
Rearranging gives;
sec²x + 4secx + 4 = 0
Factorizing the left hand side gives;
(sec x + 2)(sec x + 2) = 0
This means that;
(sec x + 2) = 0
From trigonometry, we know that sec x = 1/cos x
Thus;
(1/cos x) + 2 = 0
1/cos x = -2
cos x = -1/2
cos x = -0.5
x = cos^(-1) -0.5
x = 120°
Answer:
It will apear right after B and we can see it on the right side of B .