Answer:
M = 0.177
Explanation:
First, we have to find the molar mass of potassium iodine (KI).
K = 39.098
I = 126.904
Now, add these values together to get the molar mass of KI
39.098 + 126.904 = 166.0028
Now, it's time to do a grams to moles conversion.
35.0 g KI * =
= 0.212 mol KI
Now, we can find the molarity of this solution.
Molarity (M) =
M = = 0.177 M
The molarity (M) of this solution is 0.177.
Given :
Mass of oxygen containing carbon monoxide (CO) is 2.666 gram .
To Find :
How many grams of carbon (C) would be present in carbon monoxide (CO) that contains 2.666 grams of oxygen (O) .
Solution :
By law of constant composition , a given chemical compound always contains its component elements in fixed ratio (by mass) and does not depend on its source and method of preparation.
So , volume of solution does not matter .
Moles of oxygen , .
Now , molecule of CO contains 1 mole of C .
So , moles of C is also 0.167 mole .
Mass of carbon , .
Therefore , mass of carbon is 2 grams .
Hence , this is the required solution .