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guajiro [1.7K]
1 year ago
6

what is the concentration of hydroxide ions after 50.0 ml of 0.250 m naoh is added to 120 ml of 0.200 m na2so4? please show all

work.
Chemistry
1 answer:
Galina-37 [17]1 year ago
5 0

The concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

What is meant by concentration?

Concentration is the total amount of solute present in the given volume of solution. this is expressed in terms of molarity, molality, mole fraction, normality etc. The term concentration mostly refers to the solvents and solutes present in the solution.

Concentration of hydroxide ions can be calculated by,

M (OH^-) = V (NaOH) x M (NaOH) / V (total) = 50ml x 0.250M / 50ml + 120ml = 0.0735M = 7.35 x 10^-2 M.

where M (OH^-) = concentration of hydroxide ions, V(NaOH) = volume of NaOH, M(NaOH) = concentration of NaOH.

Therefore, the concentration of the hydroxide ions after 50 ml of 0.250M NaOH is added to 120ml of 0.200M Na2SO4 is 7.35 x 10^-2 M.

To learn more about concentration click on the given link brainly.com/question/17206790

#SPJ4

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How many grams of hcl can be produced from the reaction of 23 moles of h2 and 875g of cl2?
max2010maxim [7]

Answer: 899 g

Explanation:

Since the mass of a mole of diatomic chlorine is about 70.9 g/mol, this means that 875 grams is about 875/70.9 = 12.3 mol.

Hence, we know that chlorine is the limiting reactant, and that about 12.3 moles of chlorine will be consumed.

This means that 12.3(2)=24.6 grams of HCl will be produced, which will have a mass of about (24.6)(36.46)=899 g

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2 years ago
How many total moles of ions are released when the following sample dissolves completely in water? Enter your answer in scientif
Katena32 [7]

<u>Answer:</u> The number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

<u>Explanation:</u>

Formula units are defined as lowest whole number ratio of ions in an ionic compound. It is calculate by multiplying the number of moles by Avogadro's number which is 6.022\times 10^{23}

We are given:

Number of formula units of Sr(HCO_3)_2=4.55\times 10^{15}

As, 6.022\times 10^{23}  number of formula units are contained in 1 mole of a substance.

So, 4.55\times 10^{15} number of formula units will be contained in = \frac{1}{6.022\times 10^{23}}\times 4.55\times 10^{15}=7.5\times 10^{-9}mol of strontium bicarbonate.

Hence, the number of moles of strontium bicarbonate is 7.5\times 10^{-9}mol

5 0
3 years ago
A voltaic cell is created by using a copper cathode and a magnesium anode. The cathode is immersed in a solution of Cu2 ions, an
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Answer:

As the reaction proceeds in the given voltaic cell, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. At the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

Explanation:

A voltaic or galvanic cell is an example of an electrochemical cell.

An electrochemical cell is a device that produces an electric current from chemical reactions occuring within it.

Electrochemical cells have two electrodes; the anode and the cathode. The anode is defined as the electrode where oxidation occurs while the cathode is the electrode where reduction occurs.

The voltaic cell uses two different metal electrodes each immersed in an electrolyte solution. The two electrodes are connected to each other by means of a wire which allows the flow of electrons from the anode to the cathode. The electrolytes are connected by means of a salt bridge which is a junction that connects the electrolytic solution in the anode and cathode compartment. The salt bridge usually consists of a strong electrolyte like NaCl, KCl, Na₂SO₄, etc.

The electrolyte in the salt bridge serves two purposes: it completes the circuit by providing a path for electron flow and it maintains electrical neutrality in both solutions by allowing ions to migrate between them.

As the reaction proceeds in the given voltaic cell above, the Na₂SO₄ present in the salt bridge will dissociate into Na⁺ and SO₄²⁻ ions. As the copper ions in the solution are being deposited on the copper cathode as neutral copper atoms, the solution will become more negative, therefore the Na⁺ ions in the salt bridge will migrate into the the solution in order to maintain electrical neutrality. Also, at the anode, as the Mg metal dissolve into the solution as Mg⁺² ions, the  solution will tend to become more positive. Therefore, the SO₄²⁻ ions present in the salt bridge will migrate into the solution in order to maintain electrical neutrality.

5 0
3 years ago
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mafiozo [28]

This thermochemical equation needs to be balanced. Hence, option B is correct.

<h3>What is a balanced chemical equation?</h3>

A balanced equation contains the same number of each type of atom on both the left and right sides of the reaction arrow.

The balanced thermochemical equation is:

H_2(g) + 2NaCl (s) + 3O_2 (g) → 2HCl (l) + 2Na (s) + 2O_3 (g)

Hence, option B is correct.

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2 years ago
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worty [1.4K]

Answer:

The correct statement is:

E - The entropy of the products is greater than the entropy of the reactants.

Explanation:

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As glucose is a large molecule and then it is transformed into many molecules of water and carbon dioxide, the entropy of the system increases. If the number of molecules increases, the disorder increases.

Initial state: 7 molecules (1 glucose + 6 oxygen)

Final state: 12 molecules (6 carbon dioxide + 6 water)

3 0
3 years ago
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