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2 years ago

The elves and reindeer are getting ready for a meeting with Santa.

Mathematics

1 answer:

Feliz [49]2 years ago

3 0

Let $e$ and $r$ be the number of elves and reindeers, respectively.

We know that:

$r+e=14$ (so far 14 of them have arrived)

$4r+2e = 38$ (each reindeer has 4 legs and each elf has two)

If we multiply the first equation by 2 we have $2r+2e=28$ , and if we subtract this equation from the second we have $2r=10$ which implies $r=5$ .

So, there are 5 reindeers and 9 elves (remember that they have to sum up to 14).

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