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worty [1.4K]
3 years ago
6

The elves and reindeer are getting ready for a meeting with Santa.

Mathematics
1 answer:
Feliz [49]3 years ago
3 0

Let e and r be the number of elves and reindeers, respectively.

We know that:

r+e=14 (so far 14 of them have arrived)

4r+2e = 38(each reindeer has 4 legs and each elf has two)

If we multiply the first equation by 2 we have 2r+2e=28, and if we subtract this equation from the second we have 2r=10 which implies r=5.

So, there are 5 reindeers and 9 elves (remember that they have to sum up to 14).

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Solve 3x square - 2 x + 7 x - 5
ale4655 [162]

Answer:

The correct ans is...

3 x square + 5 x - 5

Step-by-step explanation:

U can only subtract or add if u hv the same variable..

here -2x and 7x have the same variable...

so -2x + 7x = 5x

Therefore the ans is....

3 x square + 5 x - 5

Hope this helps....

Have a GOOD DAY !!!!

Pls mark my ans as brainliest

If u mark my ans as brainliest u will get 3 extra points

Sry to say....

U really need to read ur Math TBK

7 0
3 years ago
Read 2 more answers
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antoniya [11.8K]

Answer:.

W. T. F.

it has nothing to do with a dog!?!?!?!?!!?!?!?!?!?!?

5 0
4 years ago
easy algebra question below first correct answer gets brainliest, if you put a link i will report and block
boyakko [2]

Answer:

6x²

Step-by-step explanation:

3x×2x=6...... then an x²

Therefore answer is 6x²

3 0
3 years ago
An engineer is designing a large steel pad to be installed on the deck of an aircraft carrier. Its total volume will be 18 yd^3.
Shtirlitz [24]

Answer:

The cost of the material for the full-sized pad is;

d) 222,750.00

Step-by-step explanation:

The parameters of the steel pad and the scale model are;

The volume of the deck = 18 yd³

The dimensions of the model of the same material = 6 feet by 4.5 feet and 4.5 inches thick

The weight of the sample, m₂ = 75 lbs

The cost of the steel, P = $55/lb

The dimensions of the sample in yards are;

6 feet = 2 yards, 4.5 feet = 1.5 yards, and 4 inches = 0.\overline 1 yards

The volume of the sample, V₂ = 2 yd. × 1.5 yd. × 0.\overline 1 yd. =  (1/3) yd.³

The density of the sample material, ρ = m₂/V₂

∴ The density of the sample material, ρ = 75 lbs/((1/3)yd.³) = 225 lbs/yd³

Therefore, the density of the material of the pad, ρ = 225 lbs/yd³

The mass of the steel  pad, m₁ = ρ × V₁

∴ The mass of the steel  pad, m₁ = 225 lbs/yd³ × 18 yd³ = 4,050 lbs

The cost of the material for the full-sized steel pad, C = m₁ × P

∴ C = 4,050 lbs × $55/lb = $222,750

6 0
3 years ago
Can you please help me
asambeis [7]
C. Hope this helps:)
8 0
3 years ago
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