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Nadusha1986 [10]
3 years ago
6

THE WEATHER BALLOON DATA WE STUDIED WAS MEASURED AND RECORDED AT MIDNIGHT. THE TEMPERATURE OF THE AIR AT Earth's SURFACE IS DIFF

ERENT DURING DIFFERENT TIME OF THE DAY. WHAT OTHER TIMES OF THE DAY COULD WE MEASURE THE SURFACE TEMPERATURES OUTSIDE THE SCHOOL BUILDING? WHY? Write your thought on a sticky note and add it to our board. (Please initial your note.)​
Chemistry
1 answer:
melomori [17]3 years ago
3 0

Answer night

Explanation:

because day is to hot

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When ethyl ether is heated with excess HI for several hours, the only organic product obtained is ethyl iodide. T/F
Anastasy [175]

Answer:

True

Explanation:

Ethers react with HI to form the corresponding alcohols and alkyl iodides.

Similarly, ethyl ether react with excess of HI to form ethanol and ethyl iodide. But in the excess of HI as mentioned in the question, ethanol too undergoes S^{N}2 reaction with HI to form ethyl iodide.

<u>Hence, ethyl iodide is the only product when ethyl ether reacts with excess of HI for several hours.</u>

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3 years ago
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Bogdan [553]
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3 0
4 years ago
Calculate the electrical energy per gram of anode material for the following reaction at 298 K:
solmaris [256]

43.8 kJ

<h3>Explanation</h3>

There are two electrodes in a voltaic cell. Which one is the anode?

The lithium atom used to have no oxygen atoms when it was on the reactant side. It gains two oxygen atoms after the reaction. It has gained more oxygen atoms than the manganese atom. Gaining oxygen is oxidation. As a result, lithium is being oxidized.

Oxidation takes place at the anode of a cell. Therefore, the anode of this cell is made of lithium.

Lithium has an atomic mass of 6.94. Each gram of Li would contain 1/6.94 = 0.144 moles of Li atoms. Each Li atom loses one electron in this cell. Therefore, the number of electron transferred, <em>n</em>, equals 0.144 moles for each gram of the anode.

Let w_\text{max} represents the electrical energy produced.

w_\text{max} = n \cdot F \cdot E_\text{cell}, where

  • <em>n</em> is the <em>number of moles</em> electrons transferred,
  • <em>F</em> is the Faraday's constant,
  • <em>E</em>_\text{cell} is the cell potential,

<em>n </em>= 0.144 mol, as shown above, and

<em>F </em>= 96.486 kJ / (\text{V} \cdot \text{mol} \; \text{e}^{-}).

Therefore,

w_\text{max} = n \cdot F \cdot E\\\phantom{w_\text{max}} = 0.144 \times 96.486 \times 3.15 \\\phantom{w_\text{max}} = 43.8 \; \text{kJ}.

3 0
3 years ago
5 The apparatus shown below was set up. Give explanations for the following observations.
lana [24]

Answer:

hope it helps brainliest pls

Explanation:

3 0
2 years ago
HELP ASAP 30 POINTS
allsm [11]

Answer:

Explanation:

Dind out

5 0
3 years ago
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