SA = 1,226 in.² (Hope this helps!)
We solve the inequality by subtracting 56.50 from both sides of the equation,
10.45b + 56.50 - 56.50 < 292.67 - 56.50
10.45b < 236.17
Then, divide both sides of the inequality by 10.45
b < 22.6
The solution suggests that the number of boxes than can be loaded on a truck without exceeding the weight limit of the truck should always be lesser than 22.6. Since we are talking about number of boxes, the maximum number of boxes that can be loaded should only be 22.
Yesterday, the store made $10,500 in sales
I'd say A. 8000, because you'd get the most answers and the biggest variety in answers for a more accurate sample.
