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gtnhenbr [62]
3 years ago
11

Ask Your Teacher The height h in feet reached by a dolphin t seconds after breaking the surface of the water is given by h = −16

t2 + 32t. How long will it take the dolphin to jump out of the water and touch the trainer's hand when h = 16?
Physics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

1 second

Explanation:

h = −16t² + 32t

When, h = 16

16 = −16t² + 32t

Divide each of the numbers by 16

1 = -1t² + 2t

Rearrange the equation

1t²-2t+1 = 0

Solving by the quadratic formula, we get

t=\frac{-(-2)\pm \sqrt{(-2)^2-4\times 1\times 1}}{2\times 1}\\\Rightarrow t=\frac{2\pm 0}{2}\\\Rightarrow t=1\ s

So, time taken by the dolphin to jump out of the water and touch the trainer's hand is 1 second.

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true or false? destructive interference occurs when a trough meets up with another trough given location along the medium
disa [49]

Answer:Poopy-di scoop

Scoop-diddy-whoop

Whoop-di-scoop-di-poop

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Scoopty-whoop

Whoopity-scoop, whoop-poop

Poop-diddy, whoop-scoop

Poop, poop

Scoop-diddy-whoop

Whoop-diddy-scoop

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Explanation:

4 0
3 years ago
If the mass of an object is 8 kg and its momentum is -80 kgm/s, what is its velocity?
Dimas [21]

An object's momentum is the product of its mass and its velocity:

p = mv

p is its momentum, m is its mass, and v is its velocity.

Given values:

p = -80kg×m/s

m = 8kg

Plug in these values and solve for v:

-80 = 8v

v = -10m/s

Choice D

4 0
3 years ago
In this example we see how thermal expansion can actually throw off the accuracy of a length-measuring device—namely, a tape mea
Ulleksa [173]

Answer:

The new length is 50.00885m

Explanation:

linear thermal expansion coefficient Fe 11.8e-6 /K

The new length can be determined using the following equation:

∆L/L = α∆T, where α is linear thermal expansion coefficient

∆L = Lα∆T = 50(11.8e-6)(35-20) = 0.00885 m

New length = ( 50.000 + 0.00885)m =

New length = 50.00885 m

5 0
3 years ago
Read 2 more answers
How can a karate expert break a concrete block
FinnZ [79.3K]

Many ways, but some of the most famous are kicks (side, back, front, snap) or a smash.

Hope it helped! :)

8 0
3 years ago
The spring of a spring balance is 6.0 in. long when there is no weight on the balance, and it is 8.4 in. long with 4.0 lb hung f
Sergeeva-Olga [200]

Answer:

W = 55.12 J

Explanation:

Given,

Natural length = 6 in

Force = 4 lb,  stretched length = 8.4 in

We know,

F = k x

k is spring constant

4 = k (8.4-6)

k = 1.67 lb/in

Work done to stretch the spring to 10.1 in.

W =k\int_{6}^{10.1} x

W = \dfrac{k}{2}[x^2]_6^{10.1}

W = \dfrac{1}{2}\times 1.67\times (10.1^2-6.0^2)

W = 55.12 J

Work done in stretching spring from 6 in to 10.1 in is equal to 55.12 J.

3 0
3 years ago
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