Answer:
The speed of the stone is
v = 7.45 m/s
Explanation:
Length, L=0.551m
maximum tension in the spring = 9.6%
So let speed of stone be
Tv = TH + 9.6/ 100 * TH
Tv - m*g = m*v^2/L
TH = m*v^2 / L
Factor mass to cancel in the equation
Solve to v
v^2= L*g*100 / 9.6
Replacing numeric:
v^2=0.551m*9.8m/s^2*100 / 9.6
v = sqrt( 56.24 m^2/s^2)
v = 7.45 m/s
B the energy of the car. Sorry if this is not right
Assume it is in uniform deceleration.
u=25
v=0
s=x
a=?
t=12
v=u+at
0=25+a(12)
a=-2.08(3sig fig)
decelerarion of 2.08 ms^(-2)/
acceleration=-2.08ms^(-2)
Momentum of the wagon increases by (200 x 3)
= 600 newton-sec
= 600 kg-m/sec
