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3 years ago

What is the difference between charging by contact and charging by induction in terms of electron transfer.

Physics

1 answer:

Veronika [31]3 years ago

5 0

Answer:

the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch

Explanation:

There are three methods of charging an object:

- Charging by friction: this is done by rubbing an object against another object. An example is when a plastic rod is rubbed with a wool cloth. When this is done, electrons are transferred from the wool to the rod, so both objects remain charged at the end of the process

- Charging by contact: this is done by putting in contact a charged object with a neutral, conducting object. In this case, the charges are transferred from the charged object to the neutral object; at the end of the process, the neutral object will also have a net electric charge, so it will be also charged.

- Charging by induction: in this case, we take a charged object, and a neutral object, and we place the two objects close to each other, but without touching. Let's assume that the charged object is negatively charged: in this case, the positive charges in the neutral object are attracted towards the negative charges of the charged object, while the negative charges of the neutral object are repelled away. As a result, the positive and negative charges in the neutral object split apart. If the object is connected to the ground, then negative charges move away, so the neutral object will remain positively charged.

Therefore, the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch.

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An electric field of 1139 V/m is applied to a section of silver of uniform cross section. Find the resulting current density if

N76 [4]

Answer:

So, you're going to need the equation ρ = ρo [1 + α(T-To)]

1.59x10^-8 ohms*m is your ρo because that is measured at your reference temperature (To), 20◦C. T is your 6◦C and α is 0.0038(◦C)−1. So, using that you solve for ρ. If you keep up with the units though, you notice it comes out to be ohms*m and that isn't what you want.

So, the next equation you need is J=σE where E is your electric field (3026 V/m) and σ is the electrical conductivity which is the inverse of your answer you got in the previous equation. So find the inverse of that answer and multiply it by your electric field and that will give you the current density.

I hope this helps!

Explanation:

8 0

3 years ago

Describe how sound waves propagate.

Free_Kalibri [48]

Answer:

Sound waves go back and forth sending signals to your eardrum

Explanation:

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3 years ago

How long does it take for the speed of light and sound to travel around the world

irina [24]

-- Light travels straight, not around in a circle. But if it did, it would cover
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3 years ago

For the equation BaCI2 + Na2SO4 > BaSO4 + 2NaCI

Umnica [9.8K]

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3 years ago

A 0.150 kg ball is fired from toy gun with a spring with spring constant k- 150 N/m, initially compressed by a distance x 0.050

Degger [83]

Answer:

v = 4.264 m/s

Explanation:

It is given that,

Mass of the ball, m = 0.15 kg

Spring constant of the spring, k = 150 N/m

The spring is compressed by a distance, x = 0.05 m

The pellet's initial velocity is at an angle θ (θ < 90) above the horizontal.

Let v is the final speed of the projectile when it is at a distance h = 0.800 m below its initial height. It can be calculated using the conservation of energy as :

$E_i=E_f$

$\dfrac{1}{2}kx^2+mgh=\dfrac{1}{2}mv^2$

$\dfrac{1}{2}\times 150\times (0.05)^2+0.15\times 9.8\times 0.8=\dfrac{1}{2}\times 0.15\times v^2$

v = 4.264 m/s

So, the final speed of the projectile is 4.264 m/s. Hence, this is the required solution.

3 0

3 years ago