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KIM [24]
3 years ago
13

What is the difference between charging by contact and charging by induction in terms of electron transfer.

Physics
1 answer:
Veronika [31]3 years ago
5 0

Answer:

the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch

Explanation:

There are three methods of charging an object:

- Charging by friction: this is done by rubbing an object against another object. An example is when a plastic rod is rubbed with a wool cloth. When this is done, electrons are transferred from the wool to the rod, so both objects remain charged at the end of the process

- Charging by contact: this is done by putting in contact a charged object with a neutral, conducting object. In this case, the charges are transferred from the charged object to the neutral object; at the end of the process, the neutral object will also have a net electric charge, so it will be also charged.

- Charging by induction: in this case, we take a charged object, and a neutral object, and we place the two objects close to each other, but without touching. Let's assume that the charged object is negatively charged: in this case, the positive charges in the neutral object are attracted towards the negative charges of the charged object, while the negative charges of the neutral object are repelled away. As a result, the positive and negative charges in the neutral object split apart. If the object is connected to the ground, then negative charges move away, so the neutral object will remain positively charged.

Therefore, the main difference between charging by contact and charging by induction is that in the first case, the two objects are touching, while in the second case, the two objects do not touch.

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You’ve made the hypothesis that the stepper the slope , the faster a ball will be rolling when it reaches the bottom .
BigorU [14]

Answer:

B) how steep the slope is

Explanation:

Because you have to know how is the influence of the steep of the slope in the time that a ball reaches the bottom. The steep of the slope is the variable that you would have to change in an experiment.

I hope this is useful for you

regards

4 0
3 years ago
The current in a wire varies with time according to the relationship 1=55A−(0.65A/s2)t2. (a) How many coulombs of charge pass a
mario62 [17]

Answer:

(A) Q = 321.1C (B) I = 42.8A

Explanation:

(a)Given I = 55A−(0.65A/s2)t²

I = dQ/dt

dQ = I×dt

To get an expression for Q we integrate with respect to t.

So Q = ∫I×dt =∫[55−(0.65)t²]dt

Q = [55t – 0.65/3×t³]

Q between t=0 and t= 7.5s

Q = [55×(7.5 – 0) – 0.65/3(7.5³– 0³)]

Q = 321.1C

(b) For a constant current I in the same time interval

I = Q/t = 321.1/7.5 = 42.8A.

3 0
3 years ago
Read 2 more answers
Plsssss asappppppppp
KengaRu [80]

Answer:

20 meters.

Explanation:

In the graph, the x-axis (the horizontal axis) represents the time, while the y-axis (the vertical axis) represents the distance.

If we want to find the distance covered in the first T seconds, you need to find the value T in the horizontal axis.

Once you find it, we draw a vertical line, in the point where this vertical line touches the graph, we now draw a horizontal line. This horizontal line will intersect the y-axis in a given value. That value is the total distance travelled by the time T.

In this case, we want to find the total distance that David ran in the first 4 seconds.

Then we need to find the value 4 seconds in the horizontal axis. Now we perform the above steps, and we will find that the correspondent y-value is 20.

This means that in the first 4 seconds, David ran a distance of 20 meters.

6 0
3 years ago
you give a shopping cart a job down the aisle the cart is full of groceries and has a mass of 18 kilograms the cart accelerates
mezya [45]

                 Force = (mass) x (acceleration)

                 Force = (18 kg) x (3 m/s²) = 54 newtons

As long as you continue pushing the cart with 54 newtons of force,
it will accelerate at 3 m/s². 

At the instant you release it, or keep your hands on it but stop pushing,
it will stop accelerating.  It'll continue forward at the speed it had when
the 54 newtons of force stopped.
6 0
3 years ago
Read 2 more answers
Zero, a hypothetical planet, has a mass of 5.8 x 1023 kg, a radius of 2.7 x 106 m, and no atmosphere. a 10 kg space probe is to
Tom [10]
To answer these questions just use the equations for potential energy using the mass and heights described. the potential energy at the prescribed heights = the initial kinetic energy required to reach that height.

Make sure you calculate the force of gravity on the surface using the radius of the planet.
5 0
3 years ago
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