Which of the following is the test for chlorine gas?
1 answer:
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Answer:
47,9 kJ/g
Explanation:
The enthalpy of combustion is the change in energy due the reaction of combustion of n-octane. If the enthalpy is -4,79x10⁷ J/kg And knowing (1000J = 1kJ) (1000g = 1kg). The enthalpy of combustion expressed in kJ/g is:
= <em>47,9kJ/g</em>
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Answer:
Atoms He (Avogadro’s number) → Moles of He (molar mass of He) → Mass of He
• molar mass of He (from the periodic table) = 4.003 g/mol
• Avogadro’s Number: Avogadro’s number gives us the number of entities present in 1 mole: 6.022 × 1023 He atoms in 1 mole of He
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Grams of Chromium(III) nitrate produced : 268.95 g
<h3>Further explanation</h3>Given
0.85 moles of Lead(IV) nitrate
Required
grams of Chromium(III) nitrate
Solution
Reaction
Balanced equation :
<em>2Cr₂ + 3Pb(NO₃)₄ ⇒ 4Cr(NO₃)₃ + 3Pb </em>
From the equation, mol ratio of Pb(NO₃)₄ : Cr(NO₃)₃ = 3 : 4, so mol Cr(NO₃)₃
mol Cr(NO₃)₃ =
Mass of Chromium(III) nitrate (MW=238.0108 g/mol) :
mass = mol x MW
mass = 1.13 x 238.0108
mass = 268.95 g
Answer:
<h2>12.38 g/mL</h2>Explanation:
The density of a substance can be found by using the formula
m is the mass
v is the volume
From the question
m = 149.8 g
v = 12.1 mL
We have
We have the final answer as
<h3>12.38 g/mL</h3>Hope this helps you