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Degger [83]
3 years ago
9

Write the electronic configuration of the first 20 element​

Chemistry
1 answer:
yuradex [85]3 years ago
3 0
Argon -Potassium-carbon
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Compare the type of change that occurs when an iron bar rusts and when a substance freezes.
Ivanshal [37]

Explanation:

when an iron bar rust is an example of a chemical change in which a new substance is formed and the change is not easily reversible.for iron to rust moisture and air must be present.while when a substance freezes,it can be easily reversed through melting and no new substance is formed.this change is termed a physical change.

5 0
2 years ago
What is a huge organic molecule composed of many smaller molecules called?
photoshop1234 [79]

Answer:

Macromolecules. A very large organic molecule composed of many smaller molecules, 1)Carbohydrates, 2)proteins, 3)lipids, 4)nucleic acids. Three of the four classes of macromolecules that are polymers. 1.Carbohydrates.

7 0
3 years ago
What does the atomic mass of an element on the periodic table represent?
Lynna [10]
The atomic mass on the periodic table represents the sum of number of protons and number of neutrons.

Atomic mass = Number of protons + number of neutrons

Hope this helps!
3 0
3 years ago
Someone please help! this is the last question<br>I only need help with B.<br><br>​
ludmilkaskok [199]

1. mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. Na₂CO₃ as a limiting reactant

<h3>Further explanation</h3>

Given

Reaction

2 Al(NO₃)₃ + 3 Na₂CO₃ → Al₂(CO₃)₃ + 6 NaNO₃

Required

mol ratio

Limiting reactant

Solution

The reaction coefficient in the chemical equation shows the mole ratio of the components of the compound involved in the reaction (reactants and products)

1. From the equation mol ratio of Al(NO₃)₃ : Na₂CO₃ = 2 : 3

2. mol : coefficient of Al(NO₃)₃ : Na₂CO₃ = 2 mole/2 : 2 mole/3 = 1 : 0.67

Na₂CO₃ as a limiting reactant (smaller)

6 0
3 years ago
Calculate the molarity of a salt solution with a volume of 0.250L that contains 0.70 mol of NaCl. (SHOW WORK)
Kazeer [188]

Answer:

= 0.28M

Explanation:

data:

volume = 0.250 L

           = 0.250dm^3                       ( 1litre = 1dm^3)

moles = 0.70 moles

Solution:

      molarity = \frac{no. of moles}{volume in dm^3}

                 = 0.70 / 0.250

    molarity = 0.28 M

5 0
2 years ago
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