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Degger [83]
3 years ago
9

Write the electronic configuration of the first 20 element​

Chemistry
1 answer:
yuradex [85]3 years ago
3 0
Argon -Potassium-carbon
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Which of the following processes are spontaneous? I. dissolving more solute in an unsaturated solution II. dissolving more solut
sergiy2304 [10]

Answer:

I. dissolving more solute in an unsaturated solution

Explanation:

A saturated solution is the solution which contains maximum concentration of solute dissolved in solvent. ​

However, if the solution is being provided with energy (heating) , it will dissolve more heat and the solution that cannot even dissolve more solute after heating is super saturated solution.

<u>Both saturated and supersaturated solutions have maximum of their capacity to dissolve the solute and hence further energy requires energy and these processes are non-spontaneous.</u>

<u>An unsaturated solution can dissolve more solute easily and thus is a spontaneous process.</u>

<u></u>

6 0
4 years ago
_ g of potassium reacts with 16 g of oxygen to produce 94 g of potassium oxide
natali 33 [55]
Due to the law of conservation of mass, _g K + 16g O=94g KO.
So, 94-16=78
78 is your answer
5 0
4 years ago
Read 2 more answers
A 0. 462 g sample of a monoprotic acid is dissolved in water and titrated with 0. 180 m koh. what is the molar mass of the acid
Len [333]

The molar mass of the acid if 28. 5 ml of the koh solution is required to neutralize the sample is 90.23g/mol.

<h3>For the calculation of molarity of solution</h3>

Molarity = (moles of solute/volume of solution) × 1000

Given,

Molarity of KOH solution = 0.180 M

Volume of solution = 28.5 mL

0.180 = (moles of KOH/ 28.5) × 1000

Moles = (0.18× 28.5)/1000

= 0.00513 mol

<h3>Chemical equation for the reaction</h3>

HA + KOH ------- KA + H2O

1 moles of KOH reacts with 1 moles of HA.

So, 0.00513 moles of KOH react with 0.00513 moles of HA.

<h3>To calculate the molar mass for given number of moles</h3>

Number of moles= given mass/ Molar mass

Given,

Mass of HA = 0.462 g

Moles of HA = 0.00512 mol

0.00512 = 0.462/ Molar mass

Molar mass = 90.23 g/ mol.

Thus the molar mass of HA required to neutralize the 28.5 mL of KOH is 90.23g/mol.

learn more about molar mass or moles:

brainly.com/question/26416088

#SPJ4

3 0
1 year ago
Your answer should have the same number of significant figures is the start of measurement 400.08mL —— L
Eddi Din [679]
The answer would be .40008L

The word milli- translates to \frac{1}{1000} units. In this case, we have liters as our base unit. So a milliliter is \frac{1}{1000} Liters or you can say that there are:

1,000 mL in 1 L. 

As I understand, you are trying to convert 400.08mL to L. 

So this is how you are going to get it:

400.08mL x \frac{1L}{1,000mL}
= \frac{400.08L}{1,000} = 0.40008L
3 0
4 years ago
In the reaction between the strong acid HCI and the strong base NaOH which of the ions listed below is a spectator ion?
qwelly [4]

Answer:

Na+

Explanation:

The equation would be:

HCl (aq) + NaOH (aq) --> HOH (l) + NaCl (aq)

The equation is already balanced and the NaCl will disassociate in Na+ and Cl- and HCl will disassociate into H+ and Cl- and NaOH will disassociate into Na+ and OH-. Na+ is on both sides of the equation and stays the same, so Na+ will be the spectator ion.  

3 0
3 years ago
Read 2 more answers
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