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sergey [27]
3 years ago
5

H fygykg,hyf ggyhgfsdyhcjsgvfufdgyvyghxhjlkfdhgjkygucdsgyifdc \

Chemistry
2 answers:
kirza4 [7]3 years ago
7 0

Well thats a pretty difficult question, I think the answer might be 4

Vadim26 [7]3 years ago
6 0

Answer:

For santa

From me

letter:

<em><u>Dear Santa, I want you to give me a trip to the United States or Europe, in Latin America the only good thing is food. I also want you to remove the president fachero of Argentina</u></em>

<em><u>merry christmas santa.</u></em>

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1) When solid Fe metal is put into an aqueous solution of NiSO4, solid Ni metal and a solution of FeSO4 result. Write the net io
k0ka [10]
Fe + NiSO4 ----> FeSO4 + No


NaF + HI ---> NaI + HF
7 0
3 years ago
Quick electron emissions are called
vivado [14]

Answer:

<u>Beta</u><u> </u><u>decay</u>

Quick electron emissions are called <u>beta</u><u> </u><u>decay</u>

<em>Hope</em><em> this</em><em> helps</em>

5 0
3 years ago
When 2.50 g of an unknown weak acid (ha) with a molar mass of 85.0 g/mol is dissolved in 250.0 g of water, the freezing point of
baherus [9]
When dT = Kf * molality * i
                = Kf*m*i
and when molality = (no of moles of solute) / Kg of solvent
                               = 2.5g /250g x 1 mol /85 g x1000g/kg
                               =0.1176 molal
and Kf for water = - 1.86 and dT = -0.255
by substitution 
0.255 = 1.86* 0.1176 * i
∴ i = 1.166
when the degree of dissociation formula is: when n=2 and  i = 1.166
a= i-1/n-1 = (1.166-1)/(2-1) = 0.359 by substitution by a and c(molality) in K formula
∴K = Ca^2/(1-a)
     = (0.1176 * 0.359)^2 / (1-0.359)
     = 2.8x10^-3



5 0
3 years ago
What volume of air at 25°C and 1.00 atm can he stored in a 10.0 L high-pressure air tank if compressed to 25°C and 175 atm?
DaniilM [7]

Answer:

1750L

Explanation:

Given

Initial Temperature = 25°C

Initial Pressure = 175 atm

Initial Volume = 10.0L

Final Temperature = 25°C

Final Pressure = 1 atm

Final Volume = ?

This question is an illustration of ideal gas law.

From the given parameters, the initial temperature and final temperature are the same; this implies that the system has a constant temperature.

As such, we'll make use of Boyle's Law to solve this;

Boyle's Law States that:

P₁V₁ = P₂V₂

Where P₁ and P₂ represent Initial and Final Pressure, respectively

While V₁ and V₂ represent Initial and final volume

The equation becomes

175 atm * 10L = 1 atm * V₂

1750 atm L = 1 atm * V₂

1750 L = V₂

Hence, the final volume that can be stored is 1750L

5 0
3 years ago
Fill in the blank: After a chemical reaction, the atoms of the reactant _____ to form new products.
Wewaii [24]
The atoms of the reactant rearrange to form new products.
8 0
3 years ago
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