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laila [671]
3 years ago
15

How many moles of glucose are in 19.1g of glucose?​

Chemistry
1 answer:
Crank3 years ago
3 0

Answer:

0.106 mol (3s.f.)

Explanation:

To find the number of moles, divide the mass of glucose (in grams) by its Mr. Glucose has a chemical formula of C6H12O6. To find the Mr, add all the Ar of all the atoms in C6H12O6.

Ar of C= 12, Ar of H= 1, Mr of O= 16

These Ar values can be found on the periodic table.

Mr of glucose= 6(12)+ 12(1) + 6(16)= 180

Moles of glucose

= mass ÷ mr

= 19.1 ÷ 180

= 0.106 mol (3 s.f.)

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Answer:

2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

Explanation:

Suppose x is the number of litres added to the 10% mixture than the quantity of new mixture is given as below

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Also the quantity of alcohol is given as

  • q_{old}=10 \% \, of \, 7 \, litres =0.7
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Now the equation is as

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So 2 litres of pure alcohol will be added to make the overall concentration of 9 litres of mixture as 30%.

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Calculate the mass of butane needed to produce 97.4 g of carbon dioxide. Express your answer to three significant figures and in
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Answer:

32.1 g

Explanation:

Step 1: Write the balanced combustion reaction

C₄H₁₀ + 6.5 O₂ ⇒ 4 CO₂ + 5 H₂O

Step 2: Calculate the moles corresponding to 97.4 g of CO₂

The molar mass of CO₂ is 44.01 g/mol.

97.4 g × 1 mol/44.01 g = 2.21 mol

Step 3: Calculate the moles of butane that produced 2.21 moles of carbon dioxide

The molar ratio of C₄H₁₀ to CO₂ is 1:4. The moles of C₄H₁₀ required are 1/4 × 2.21 mol = 0.553 mol

Step 4: Calculate the mass corresponding to 0.553 moles of C₄H₁₀

The molar mass of C₄H₁₀ is 58.12 g/mol.

0.553 mol × 58.12 g/mol = 32.1 g

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Answer:

False

Explanation:

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Eukaryotes are a cell or cells in which the genetic material of DNA is in the form of chromosomes. This includes all living things other than eubacteria and archaebacteria.

<u><em>Hope this helps!</em></u>

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