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3 years ago

A man walks 2.6 miles east, then turns and walks 6.7 miles north. What is his resultant

Physics

1 answer:

Zarrin [17]3 years ago

6 0

Answer:

Yes cause he walks 6.7 miles

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If two micro coulomb of charge is flowing in a circuit for 5 minutes. What is the amount of current in the circuit?

Murrr4er [49]

Answer:

6.67×10¯⁹ A

Explanation:

From the question given above, the following data were obtained:

Quantity of electricity (Q) = 2 μC

Time (t) = 5 mins

Current (I) =?

Next, we shall convert 2 μC to C. This can be obtained as follow:

1 μC = 1×10¯⁶ C

Therefore,

2 μC = 2 μC × 1×10¯⁶ C / 1 μC

2 μC = 2×10¯⁶ C

Next, we shall convert 5 mins to seconds. This can be obtained as follow:

1 min = 60 secs

Therefore,

5 min = 5 min × 60 sec / 1 min

5 mins = 300 s

Finally, we shall determine the current in the circuit. This can be obtained as follow:

Quantity of electricity (Q) = 2×10¯⁶ C

Time (t) = 300 s

Current (I) =?

Q = It

2×10¯⁶ = I × 300

Divide both side by 300

I = 2×10¯⁶ / 300

I = 6.67×10¯⁹ A

Thus, the current in the circuit is 6.67×10¯⁹ A

4 0

3 years ago

If 35 J of work was performed in 70 seconds, how much power was used to do this task?

Irina18 [472]

$P = w \times delta \: T$
P = Power
W = Work
Delta T = Change of Time

So:
P = 35 Joules
Delta T = 70 secs
W = ?

$P = 35 \div 70 \\ P = 0.5 \: watts$

* Joule/Sec = Watt

Answer: The power used to do this task was 0.5 Watts.

5 0

3 years ago

Young's double slit experiment is one of the classic tests for the wave nature of light. In an experiment using red light (λ = 6

Marianna [84]

Answer:

The separation distance between the slits is 16710.32 nm.

Explanation:

Given that,

Wavelength = 641 nm

Angle =4.4°

(a). We need to calculate the separation distance between the slits

Using formula of young's double slit

$d\sin\theta=m\lambda$

$d=\dfrac{m\lambda}{\sin\theta}$

Where, d = the separation distance between the slits

m = number of order

$\lambda$ =wavelength

Put the value into the formula

$d=\dfrac{2\times641\times10^{-9}}{\sin4.4}$

$d=0.00001671032\ m$

$d=16710.32\ nm$

Hence, The separation distance between the slits is 16710.32 nm.

3 0

3 years ago

In an engine, an almost ideal gas is compressed adiabatically to half its volume. In doing so, 2820 J of work is done on the gas

Dmitry_Shevchenko [17]

Answer:

$Q=0$
$U=2820$
Energy increases

Explanation:

From the question we are told that

Work done $W=2820$

a)Generally the heat flow for an adiabatic process is 0 (zero)

$Q= U + W =>0$

$Q=0$

b)Generally Change in internal energy of gas is mathematically given by

Since $W=-2820J$

Therefore

$U=2820$

Giving

$Q= 2820 -2820$

$Q=O$

c)With increases in internal energy brings increase in temperature

Therefore

Energy increases

3 0

3 years ago

The chart shows the densities of four substances.

stiks02 [169]

Answer:

Y, X, Z, W

Explanation:

I took the test.

3 0

3 years ago

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